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प्रश्न
P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. Show that ar (APB) = ar (BQC).
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उत्तर
It can be observed that ΔBQC and parallelogram ABCD lie on the same base BC and these are between the same parallel lines AD and BC.
∴Area (ΔBQC) = 1/2Area (ABCD) ... (1)
Similarly, ΔAPB and parallelogram ABCD lie on the same base AB and between the same parallel lines AB and DC.
∴ Area (ΔAPB) = 1/2Area (ABCD) ... (2)
From equation (1) and (2), we obtain
Area (ΔBQC) = Area (ΔAPB)
संबंधित प्रश्न
In the given figure, P is a point in the interior of a parallelogram ABCD. Show that
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[Hint: Through. P, draw a line parallel to AB]
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ar (BPC) = ar (DPQ).
[Hint: Join AC.]
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