मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान इयत्ता ११

P an Apple Falls from a Tree. an Insect in the Apple Finds that the Earth is Falling Towards It with an Acceleration G. Who Exerts the Force Needed to Accelerate the Earth with this Acceleration G? - Physics

Advertisements
Advertisements

प्रश्न

An apple falls from a tree. An insect in the apple finds that the earth is falling towards it with an acceleration g. Who exerts the force needed to accelerate the earth with this acceleration g?

टीपा लिहा
Advertisements

उत्तर

The mutual gravitational force between the apple and the Earth is responsible for the acceleration produced in the apple falling from the tree. Although the Earth will experience the same force, it does not get attracted towards the apple because of its large mass. The insect feels that the Earth is falling towards the apple with an acceleration g because of the the relative motion.
let
vae = velocity of apple w.r.t earth
\[V_{ea} = \text {velocity of earth w . r . t apple }\]
\[v_{ae} = v_a - v_e = - ( v_e - v_a ) = - v_{ea}\]
As the insect is in the frame of apple so he sees the earth moving with a relative velocity \[v_{ea}\].
Any other observer on earth will see the apple moving towards earth with velocity \[v_{ae}\].
Both are opposite in direction.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 11: Gravitation - Short Answers [पृष्ठ २२३]

APPEARS IN

एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
पाठ 11 Gravitation
Short Answers | Q 7 | पृष्ठ २२३

संबंधित प्रश्‍न

The earth revolves round the sun because the sun attracts the earth. The sun also attracts the moon and this force is about twice as large as the attraction of the earth on the moon. Why does the moon not revolve round the sun? Or does it?


The acceleration of the moon just before it strikes the earth in the previous question is


If the acceleration due to gravity at the surface of the earth is g, the work done in slowly lifting a body of mass m from the earth's surface to a height R equal to the radius of the earth is


Take the effect of bulging of earth and its rotation in account. Consider the following statements :

(A) There are points outside the earth where the value of g is equal to its value at the equator.
(B) There are points outside the earth where the value of g is equal to its value at the poles.


Find the acceleration due to gravity of the moon at a point 1000 km above the moon's surface. The mass of the moon is 7.4 × 1022 kg and its radius is 1740 km.


Find the height over the Earth's surface at which the weight of a body becomes half of its value at the surface.


Find the acceleration due to gravity in a mine of depth 640 m if the value at the surface is 9.800 m s−2. The radius of the earth is 6400 km.


A body is weighed by a spring balance to be 1.000 kg at the North Pole. How much will it weigh at the equator? Account for the earth's rotation only.


A particle is fired vertically upward from earth's surface and it goes up to a maximum height of 6400 km. Find the initial speed of particle.


A particle is fired vertically upward with a speed of 15 km s−1. With what speed will it move in interstellar space. Assume only earth's gravitational field.


Explain the variation of g with depth from the Earth’s surface.


If both the mass and the radius of the earth decrease by 1%, then the value of acceleration due to gravity will


Which of the following options are correct?

  1. Acceleration due to gravity decreases with increasing altitude.
  2. Acceleration due to gravity increases with increasing depth (assume the earth to be a sphere of uniform density).
  3. Acceleration due to gravity increases with increasing latitude.
  4. Acceleration due to gravity is independent of the mass of the earth.

If R is the radius of the earth and g is the acceleration due to gravity on the earth's surface, the mean density of the earth is ______.


A pebble is thrown vertically upwards from the bridge with an initial velocity of 4.9 m/s. It strikes the water after 2 s. If acceleration due to gravity is 9.8 m/s2. The height of the bridge and velocity with which the pebble strikes the water will respectively be ______.


If the radius of the earth shrinks by 2% while its mass remains the same. The acceleration due to gravity on the earth's surface will approximately ______.


The percentage decrease in the weight of a rocket, when taken to a height of 32 km above the surface of the earth will, be ______.

(Radius of earth = 6400 km)


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×