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Integrate the function: sin8x-cos8x1-2sin2xcos2x - Mathematics

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प्रश्न

Integrate the function:

`(sin^8 x - cos^8 x)/(1-2sin^2 x cos^2 x)`

बेरीज
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उत्तर

Let `I = int (sin^8 x - cos^8 x)/ (1 - 2 sin^2x cos^2 x) dx`

We have, (sin8x - cos8x)

= (sin4x + cos4x) (sin4x - cos4x)

= [(sin2x + cos2x)2 - 2 sin2x cos2 x] (sin2 x + cos2 x) (sin2 x - cos2 x)

= (1 - 2 sin2x cos2x) (1) (-cos2x)

∴ `I = int ((1 - 2 sin^2 x cos^2 x) (- cos 2x))/(1 - 2 sin^2 x cos x)  dx`

`= - int cos 2x dx`

`= -1/2 sin2x + C`

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पाठ 7: Integrals - Exercise 7.12 [पृष्ठ ३५२]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 7 Integrals
Exercise 7.12 | Q 10 | पृष्ठ ३५२

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