मराठी

In the Following Verify that the Given Functions (Explicit Or Implicit) is a Solution of the Corresponding Differential Equation:- Y = Cos X + C Y' + Sin X = 0

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प्रश्न

In the following verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation:-

y = cos x + C            y' + sin x = 0

बेरीज
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उत्तर

We have,
y' + sin x = 0 .....(1)
Now,
y = cos x + C
⇒ y' = −sin x
Putting the above value in (1), we get
LHS = −sin x + sin x = 0 = RHS
Thus, y = cos x + C is the solution of the given differential equation.

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पाठ 21: Differential Equations - Revision Exercise [पृष्ठ १४४]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 21 Differential Equations
Revision Exercise | Q 3.3 | पृष्ठ १४४

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