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In Δ ABC, if sin2 A + sin2 B = sin2 C, then show that the triangle is a right-angled triangle. - Mathematics and Statistics

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प्रश्न

In Δ ABC, if sin2 A + sin2 B = sin2 C, then show that the triangle is a right-angled triangle.

बेरीज
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उत्तर

By sine rule,

`"sin A"/"a" = "sin B"/"b" = "sin C"/"c "` = k

∴ sin A = ka, sin B = kb, sin C = kc 

∴ sin2A + sin2B = sin2C

∴ k2a2 + k2b2 = k2c2

∴ a2 + b2 = c2

∴ Δ ABC is a rightangled triangle, rightangled at C.

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पाठ 3: Trigonometric Functions - Miscellaneous exercise 3 [पृष्ठ ११०]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 3 Trigonometric Functions
Miscellaneous exercise 3 | Q 15 | पृष्ठ ११०

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