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In ΔABC, if cos Aacos Bbcos Aa=cos Bb, then show that it is an isosceles triangle. - Mathematics and Statistics

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प्रश्न

In ΔABC, if `"cos A"/"a" = "cos B"/"b"`, then show that it is an isosceles triangle.

बेरीज
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उत्तर

Given: `"cos A"/"a" = "cos B"/"b"`      ....(1)

By sine rule,

`"a"/"sin A" = "b"/"sin B" = "k"`

∴ a = k sin A, b = k sin B

∴ (1) gives,

`"cos A"/"k sin A" = "cos B"/"k sin B"`

∴ `"cos A"/"sin A" = "cos B"/"sin B"`

∴ sin A cos B = cos A sin B

∴ sin A cos B – cos A sin B = 0

∴ sin (A – B) = 0 = sin 0

∴ A – B = 0

∴ A = B

∴ The triangle is an isosceles triangle.

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पाठ 3: Trigonometric Functions - Miscellaneous exercise 3 [पृष्ठ ११०]

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