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In Δ ABC, if a, b, c are in A.P., then show that cot ABCA2,cot B2,cot C2 are also in A.P.

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प्रश्न

In Δ ABC, if a, b, c are in A.P., then show that cot `"A"/2, cot  "B"/2, cot  "C"/2` are also in A.P.

बेरीज
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उत्तर

a, b, c are in A.P.

∴ 2b = a + c       ....(1)

Now,

`cot  "A"/2 + cot  "C"/2`

`= (cos  "A"/2)/(sin  "A"/2)  +  (cos  "C"/2)/(sin  "C"/2)`

`= (cos  "A"/2 . sin  "C"/2 + sin  "A"/2. cos  "C"/2)/(sin  "A"/2. sin  "C"/2)`

`= (sin  ("A"/2 + "C"/2))/(sin  "A"/2. sin  "C"/2)`

`= (sin  (pi/2 - "B"/2))/(sqrt((("s - b")("s - c"))/"bc"). sqrt((("s - a")("s - b"))/"ab"))`    .....[∵ A + B + C = π]

`= (cos  "B"/2)/((("s - b")/"b"). sqrt((("s - c")("s - a"))/"ca")`

`= ("b cos"  "B"/2)/(("s - b"). sin  "B"/2)`

`= "b"/("s - b"). cot  "B"/2`

`= "b"/((("a + b + c")/2 - "b")). cot  "B"/2`   ....[∵ 2s = a + b + c]

`= ("2b"/("a + c - b")).cot  "B"/2`

`= "2b"/(("2b - b")). cot  "B"/2`    ....[By (1)]

`= "2b"/"b".cot  "B"/2`

∴ `cot  "A"/2 +  cot  "C"/2 = 2 cot  "B"/2`

Hence, `cot  "A"/2,  cot  "B"/2,  cot  "C"/2` are in A.P.

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पाठ 3: Trigonometric Functions - Miscellaneous exercise 3 [पृष्ठ १०९]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 3 Trigonometric Functions
Miscellaneous exercise 3 | Q 12 | पृष्ठ १०९

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