मराठी

In a δAbc, If ∠A = 60°, ∠B = 80° and the Bisectors of ∠B and ∠C Meet at O, Then ∠Boc =

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प्रश्न

In a ΔABC, if ∠A = 60°, ∠B = 80° and the bisectors of ∠B and ∠C meet at O, then ∠BOC =

पर्याय

  • 60°

  • 120°

  • 150°

  • 30°

MCQ
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उत्तर

In the given ΔABC,∠A = 60° and ∠B = 80° . Bisectors of ∠B and ∠C meet at O. 

We need to find  ∠BOC

Since, OB is the bisector of ∠B.

Thus, `∠OBC = 1/2 ∠ABC   .....  (1)` 

Now, using the angle sum property of the triangle

In ΔABC, we get,

∠A + ∠B + ∠C =180°

   60° + 80° + ∠C = 180°

         140° + ∠C = 180°

                   ∠C = 180° - 140°

                   ∠C = 40°

Similarly, in ΔBOC

∠OBC + ∠O + ∠OCB = 180

              ∠O + 20° + 40°=180°

                     ∠O + 60° = 180°

                             ∠O = 180° - 60°

                                   = 120°

Hence, ∠BOC = 120°

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पाठ 11: Triangle and its Angles - Exercise 11.4 [पृष्ठ २५]

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आर.डी. शर्मा Mathematics [English] Class 9
पाठ 11 Triangle and its Angles
Exercise 11.4 | Q 11 | पृष्ठ २५

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