Advertisements
Advertisements
प्रश्न
In a parallelogram ABCD ∠C = 98°. Find ∠A and ∠B.
Advertisements
उत्तर
ABCD is a parallelogram
∠C = 98°
∴ ∠A = ∠C = 98° ....(opposite angles of a parallelogram are equal)
∠A + ∠B +∠C + ∠D = 360° ....(Sum of all angles of a quadrilateral = 360°)
98° + ∠B + 98° + ∠D = 360°
∠B + 196 + ∠D = 360°
∠B + ∠D = 360° - 196°
∠B +∠D = 164°
But ∠B = ∠D ....(opposite angles of a parallelogram are equal)
⇒ 2∠B = 164°
⇒ ∠B = 82° = ∠D
Therefore,
∠B = 82°, ∠A = 98°.
APPEARS IN
संबंधित प्रश्न
In the following figure, ABCD and PQRS are two parallelograms such that ∠D = 120° and ∠Q = 70°.
Find the value of x.
In case of a parallelogram
prove that:
(i) The bisectors of any two adjacent angles intersect at 90o.
(ii) The bisectors of the opposite angles are parallel to each other.
In the following figures, find the remaining angles of the parallelogram
In the following figures, find the remaining angles of the parallelogram
The angles of a triangle formed by 2 adjacent sides and a diagonal of a parallelogram are in the ratio 1 : 5 : 3. Calculate the measures of all the angles of the parallelogram.
PQR is a triangle formed by the adjacent sides PQ and QR and diagonal PR of a parallelogram PQRS. If in ΔPQR, ∠P : ∠Q : ∠R = 3 : 8 : 4, Calculate the measures of all the angles of parallelogram PQRS.
Opposite angles of a quadrilateral ABCD are equal. If AB = 4 cm, determine CD.
If PQRS is a parallelogram, then ∠P – ∠R is equal to ______.
In parallelogram FIST, find ∠SFT, ∠OST and ∠STO.
