Advertisements
Advertisements
प्रश्न
In a parallelogram ABCD ∠C = 98°. Find ∠A and ∠B.
Advertisements
उत्तर
ABCD is a parallelogram
∠C = 98°
∴ ∠A = ∠C = 98° ....(opposite angles of a parallelogram are equal)
∠A + ∠B +∠C + ∠D = 360° ....(Sum of all angles of a quadrilateral = 360°)
98° + ∠B + 98° + ∠D = 360°
∠B + 196 + ∠D = 360°
∠B + ∠D = 360° - 196°
∠B +∠D = 164°
But ∠B = ∠D ....(opposite angles of a parallelogram are equal)
⇒ 2∠B = 164°
⇒ ∠B = 82° = ∠D
Therefore,
∠B = 82°, ∠A = 98°.
APPEARS IN
संबंधित प्रश्न
In a parallelogram `square`ABCD, If ∠A = (3x + 12)°, ∠B = (2x - 32)° then find the value of x and then find the measures of ∠C and ∠D.
In the following figure, ABCD is a parallelogram. 
Prove that:
(i) AP bisects angle A.
(ii) BP bisects angle B
(iii) ∠DAP + ∠BCP = ∠APB
In the following figures, find the remaining angles of the parallelogram
In the following figures, find the remaining angles of the parallelogram
In the following figures, find the remaining angles of the parallelogram
In the following figures, find the remaining angles of the parallelogram
The consecutive angles of a parallelogram are in the ratio 3:6. Calculate the measures of all the angles of the parallelogram.
In the given figure, ABCD is a parallelogram, find the values of x and y.
If PQRS is a parallelogram, then ∠P – ∠R is equal to ______.
In the given parallelogram YOUR, ∠RUO = 120° and OY is extended to point S such that ∠SRY = 50°. Find ∠YSR.
