मराठी

If Z = 1 ( 2 + 3 I ) 2 , than | Z | =

Advertisements
Advertisements

प्रश्न

\[\text { If } z = \frac{1}{(2 + 3i )^2}, \text { than } \left| z \right| =\]

पर्याय

  • \[\frac{1}{13}\]

  • \[\frac{1}{5}\]

  • \[\frac{1}{12}\]

  • none of these

MCQ
Advertisements

उत्तर

\[\frac{1}{13}\]

\[\text { Let } z = \frac{1}{\left( 2 + 3i \right)^2}\]

\[ \Rightarrow z = \frac{1}{4 + 9 i^2 + 12i} \]

\[ \Rightarrow z = \frac{1}{4 - 9 + 12i} \]

\[ \Rightarrow z = \frac{1}{- 5 + 12i}\]

\[\Rightarrow z=\frac{1}{- 5 + 12i}\times\frac{- 5 - 12i}{- 5 - 12i}\]

\[\Rightarrow z=\frac{- 5 - 12i}{25 + 144}\]

\[ \Rightarrow z=\frac{- 5}{169}-\frac{12i}{169}\]

\[\Rightarrow\left| z \right|=\sqrt{\frac{25}{{169}^2} + \frac{144}{{169}^2}}\]

\[\Rightarrow \left| z \right|=\frac{1}{\sqrt{169}}\]

\[\Rightarrow \left| z \right| = \frac{1}{13}\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 13: Complex Numbers - Exercise 13.6 [पृष्ठ ६५]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
पाठ 13 Complex Numbers
Exercise 13.6 | Q 21 | पृष्ठ ६५

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

If a + ib  = `(x + i)^2/(2x^2 + 1)` prove that a2 + b2 = `(x^2 + 1)^2/(2x + 1)^2`


Evaluate the following:

(ii) i528


Find the value of the following expression:

(1 + i)6 + (1 − i)3


Express the following complex number in the standard form a + i b:

\[\frac{1}{(2 + i )^2}\]


Find the real value of x and y, if `((1+i)x-2i)/(3+i) + ((2-3i)y+i)/(3-i) = i, xy ∈ R, i = sqrt-1`


Find the multiplicative inverse of the following complex number:

1 − i


Find the multiplicative inverse of the following complex number:

\[(1 + i\sqrt{3} )^2\]


If \[x + iy = \frac{a + ib}{a - ib}\] prove that x2 + y2 = 1.


Find the least positive integral value of n for which  \[\left( \frac{1 + i}{1 - i} \right)^n\] is real.


If \[\frac{\left( 1 + i \right)^2}{2 - i} = x + iy\]  find x + y.


If \[\left( \frac{1 - i}{1 + i} \right)^{100} = a + ib\] find (a, b).


Evaluate the following:

\[x^4 + 4 x^3 + 6 x^2 + 4x + 9, \text { when } x = - 1 + i\sqrt{2}\]


If \[\left| z + 1 \right| = z + 2\left( 1 + i \right)\],find z.


Find the number of solutions of \[z^2 + \left| z \right|^2 = 0\].


Express the following complex in the form r(cos θ + i sin θ):
1 + i tan α


Express the following complex in the form r(cos θ + i sin θ):

 tan α − i


Find z, if \[\left| z \right| = 4 \text { and }\arg(z) = \frac{5\pi}{6} .\]


Write the value of \[\sqrt{- 25} \times \sqrt{- 9}\].


For any two complex numbers z1 and z2 and any two real numbers a, b, find the value of \[\left| a z_1 - b z_2 \right|^2 + \left| a z_2 + b z_1 \right|^2\].


If `(3+2i sintheta)/(1-2 i sin theta)`is a real number and 0 < θ < 2π, then θ =


The least positive integer n such that \[\left( \frac{2i}{1 + i} \right)^n\] is a positive integer, is.

 

If z is a non-zero complex number, then \[\left| \frac{\left| z \right|^2}{zz} \right|\] is equal to


If (x + iy)1/3 = a + ib, then \[\frac{x}{a} + \frac{y}{b} =\]


The argument of \[\frac{1 - i\sqrt{3}}{1 + i\sqrt{3}}\] is


\[\text { If } z = \frac{1}{(1 - i)(2 + 3i)}, \text { than } \left| z \right| =\]


If \[z = \frac{1}{1 - cos\theta - i sin\theta}\] then Re (z) =


The amplitude of \[\frac{1 + i\sqrt{3}}{\sqrt{3} + i}\] is 


The value of (i5 + i6 + i7 + i8 + i9) / (1 + i) is


If \[f\left( z \right) = \frac{7 - z}{1 - z^2}\] , where \[z = 1 + 2i\] then \[\left| f\left( z \right) \right|\] is


A real value of x satisfies the equation  \[\frac{3 - 4ix}{3 + 4ix} = a - ib (a, b \in \mathbb{R}), if a^2 + b^2 =\]


Find a and b if (a + ib) (1 + i) = 2 + i


Express the following in the form of a + ib, a, b ∈ R i = `sqrt(−1)`. State the values of a and b:

`(2 + sqrt(-3))/(4 + sqrt(-3))`


Show that `(-1 + sqrt(3)"i")^3` is a real number


Find the value of `(3 + 2/i) (i^6 - i^7) (1 + i^11)`.


Evaluate the following : i35 


Evaluate the following : `1/"i"^58`


Evaluate the following : i–888 


State True or False for the following:

The order relation is defined on the set of complex numbers.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×