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Express the following complex number in the standard form a + ib: (2+ЁЭСЦ)32+3тБвЁЭСЦ - Mathematics

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Express the following complex number in the standard form a + ib:

\[\frac{(2 + i )^3}{2 + 3i}\]

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\[\frac{\left( 2 + i \right)^3}{2 + 3i}\]

\[ = \frac{\left( 4 + i^2 + 4i \right)\left( 2 + i \right)}{2 + 3i} \left( \because i^2 = - 1 \right)\]

\[ = \frac{8 + 2 i^2 + 8i + 4i + i^3 + 4 i^2}{2 + 3i} \]

\[ = \frac{2 + 11i}{2 + 3i} \times \frac{2 - 3i}{2 - 3i}\]

\[ = \frac{4 - 6i + 22i - 33 i^2}{4 - 9 i^2}\]

\[ = \frac{37 + 16i}{4 + 9}\]

\[ = \frac{37}{13} + \frac{16}{13}i\]

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рдкрд╛рда 13: Complex Numbers - Exercise 13.2 [рдкреГрд╖реНрда рейрез]

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рдЖрд░рдбреА рд╢рд░реНрдорд╛ Mathematics [English] Class 11
рдкрд╛рда 13 Complex Numbers
Exercise 13.2 | Q 1.05 | рдкреГрд╖реНрда рейрез

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Disclaimer: There is a misprinting in the question. It should be  \[\left( 1 + i\sqrt{3} \right)\]  instead of \[\left( 1 + \sqrt{3} \right)\].


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Column A Column B
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segment joining (–2, 0)
and (2, 0).
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having centre at (0, –4)
and radius 3.
(c) If |z + 2| = |z − 2|, then locus of z is (iii) `(2pi)/3`
(d) If |z + 2i| = |z − 2i|, then locus of z is (iv) Perpendicular bisector of
segment joining (0, –2) and (0, 2).
(e) Region represented by |z + 4i| ≥ 3 is  (v) `2(cos  pi/6 + i sin  pi/6)`
(f) Region represented by |z + 4| ≤ 3 is  (vi) On or inside the circle having
centre (–4, 0) and radius 3 units.
(g) Conjugate of `(1 + 2i)/(1 - i)` lies in (vii) First quadrant
(h) Reciprocal of 1 – i lies in (viii) Third quadrant

Show that `(-1+ sqrt(3)i)^3` is a real number.


Find the value of `(i^(592) + i^(590) + i^(588) + i^(586) + i^(584))/(i^(582) + i^(580) + i^(578) + i^(576) + i^(574))`


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