मराठी

Find the Number of Solutions of Z 2 + | Z | 2 = 0 .

Advertisements
Advertisements

प्रश्न

Find the number of solutions of \[z^2 + \left| z \right|^2 = 0\].

Advertisements

उत्तर

Let \[z = x + iy\].

Then,

\[\left| z \right| = \sqrt{x^2 + y^2}\]

\[\therefore z^2 + \left| z \right|^2 = 0\]

\[ \Rightarrow \left( x + iy \right)^2 + \left( \sqrt{x^2 + y^2} \right)^2 = 0\]

\[ \Rightarrow x^2 + i^2 y^2 + 2ixy + x^2 + y^2 = 0\]

\[ \Rightarrow x^2 - y^2 + 2ixy + x^2 + y^2 = 0\]

\[ \Rightarrow 2 x^2 + 2ixy = 0\]

\[ \Rightarrow 2x(x + iy) = 0\]

\[ \Rightarrow x = 0 \text { or } x + iy = 0\]

\[ \Rightarrow x = 0 \text { or } z = 0\]

For

\[x = 0, z = 0 + iy\]

​Thus, there are infinitely many solutions of the form 

\[z = 0 + iy, y \in R\]
shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 13: Complex Numbers - Exercise 13.2 [पृष्ठ ३३]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
पाठ 13 Complex Numbers
Exercise 13.2 | Q 26 | पृष्ठ ३३

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Express the given complex number in the form a + ib: i–39


Express the given complex number in the form a + ib:

`[(1/3 + i 7/3) + (4 + i 1/3)] -(-4/3 + i)`


Evaluate: `[i^18 + (1/i)^25]^3`


If a + ib  = `(x + i)^2/(2x^2 + 1)` prove that a2 + b2 = `(x^2 + 1)^2/(2x + 1)^2`


Evaluate the following:

(ii) i528


Evaluate the following:

\[\left( i^{41} + \frac{1}{i^{257}} \right)^9\]


Find the value of the following expression:

(1 + i)6 + (1 − i)3


Express the following complex number in the standard form a + i b:

\[(1 + i)(1 + 2i)\]


Express the following complex number in the standard form a + i b:

\[\frac{3 - 4i}{(4 - 2i)(1 + i)}\]


If \[z_1 = 2 - i, z_2 = 1 + i,\text {  find } \left| \frac{z_1 + z_2 + 1}{z_1 - z_2 + i} \right|\]


If \[z_1 = 2 - i, z_2 = - 2 + i,\] find 

Im `(1/(z_1overlinez_1))`


Evaluate the following:

\[x^4 + 4 x^3 + 6 x^2 + 4x + 9, \text { when } x = - 1 + i\sqrt{2}\]


Solve the system of equations \[\text { Re }\left( z^2 \right) = 0, \left| z \right| = 2\].


If z1 is a complex number other than −1 such that \[\left| z_1 \right| = 1\] and \[z_2 = \frac{z_1 - 1}{z_1 + 1}\] then show that the real parts of z2 is zero.


Write (i25)3 in polar form.


Express the following complex in the form r(cos θ + i sin θ):
1 + i tan α


Express the following complex in the form r(cos θ + i sin θ):

 tan α − i


If n is any positive integer, write the value of \[\frac{i^{4n + 1} - i^{4n - 1}}{2}\].


Write the argument of −i.


Write the sum of the series \[i + i^2 + i^3 + . . . .\] upto 1000 terms.


If \[\left| z + 4 \right| \leq 3\], then find the greatest and least values of \[\left| z + 1 \right|\].


Find the real value of a for which \[3 i^3 - 2a i^2 + (1 - a)i + 5\] is real.


If \[z = \frac{- 2}{1 + i\sqrt{3}}\],then the value of arg (z) is


If z is a non-zero complex number, then \[\left| \frac{\left| z \right|^2}{zz} \right|\] is equal to


\[\text { If  }z = 1 - \text { cos }\theta + i \text { sin }\theta, \text { then } \left| z \right| =\]


The value of (i5 + i6 + i7 + i8 + i9) / (1 + i) is


\[\frac{1 + 2i + 3 i^2}{1 - 2i + 3 i^2}\] equals


The value of \[\frac{i^{592} + i^{590} + i^{588} + i^{586} + i^{584}}{i^{582} + i^{580} + i^{578} + i^{576} + i^{574}} - 1\] is 


If the complex number \[z = x + iy\] satisfies the condition \[\left| z + 1 \right| = 1\], then z lies on


Simplify : `4sqrt(-4) + 5sqrt(-9) - 3sqrt(-16)`


Find a and b if (a + ib) (1 + i) = 2 + i


Evaluate the following : i–888 


Evaluate the following : i30 + i40 + i50 + i60 


Match the statements of column A and B.

Column A Column B
(a) The value of 1 + i2 + i4 + i6 + ... i20 is (i) purely imaginary complex number
(b) The value of `i^(-1097)` is (ii) purely real complex number
(c) Conjugate of 1 + i lies in (iii) second quadrant
(d) `(1 + 2i)/(1 - i)` lies in (iv) Fourth quadrant
(e) If a, b, c ∈ R and b2 – 4ac < 0, then
the roots of the equation ax2 + bx + c = 0
are non real (complex) and
(v) may not occur in conjugate pairs
(f) If a, b, c ∈ R and b2 – 4ac > 0, and
b2 – 4ac is a perfect square, then the
roots of the equation ax2 + bx + c = 0
(vi) may occur in conjugate pairs

If w is a complex cube-root of unity, then prove the following

(w2 + w − 1)3 = −8


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×