मराठी

Evaluate the Following:\[\Left( I^{41} + \Frac{1}{I^{257}} \Right)^9\] - Mathematics

Advertisements
Advertisements

प्रश्न

Evaluate the following:

\[\left( i^{41} + \frac{1}{i^{257}} \right)^9\]

Advertisements

उत्तर

\[\left( i^{41} + \frac{1}{i^{257}} \right)^9 = \left( i^{4 \times 10 + 1} + \frac{1}{i^{4 \times 64 + 1}} \right)^9 \]

\[ = \left[ \left( i^4 \right)^{10} \times i + \frac{1}{\left( i^4 \right)^{64} \times i} \right]^9 \]

\[ = \left( i + \frac{1}{i} \right)^9 \left(\because i^4 = 1\right)\]

\[= \left( i + \frac{i}{i^2} \right)^9 \]

\[ = \left( i - i \right)^9 \left( \because i^2 = - 1 \right)\]

\[ = 0\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 13: Complex Numbers - Exercise 13.1 [पृष्ठ ३]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 11
पाठ 13 Complex Numbers
Exercise 13.1 | Q 1.5 | पृष्ठ ३

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Evaluate: `[i^18 + (1/i)^25]^3`


Evaluate the following:

\[i^{37} + \frac{1}{i^{67}}\].


Evaluate the following:

\[i^{49} + i^{68} + i^{89} + i^{110}\]


Find the value of the following expression:

i49 + i68 + i89 + i110


Find the value of the following expression:

i + i2 + i3 + i4


Find the value of the following expression:

\[\frac{i^{592} + i^{590} + i^{588} + i^{586} + i^{584}}{i^{582} + i^{580} + i^{578} + i^{576} + i^{574}}\]


Express the following complex number in the standard form a + i b:

\[(1 + i)(1 + 2i)\]


If \[z_1 = 2 - i, z_2 = 1 + i,\text {  find } \left| \frac{z_1 + z_2 + 1}{z_1 - z_2 + i} \right|\]


For a positive integer n, find the value of \[(1 - i )^n \left( 1 - \frac{1}{i} \right)^n\].


Solve the system of equations \[\text { Re }\left( z^2 \right) = 0, \left| z \right| = 2\].


If z1 is a complex number other than −1 such that \[\left| z_1 \right| = 1\] and \[z_2 = \frac{z_1 - 1}{z_1 + 1}\] then show that the real parts of z2 is zero.


If \[\left| z + 1 \right| = z + 2\left( 1 + i \right)\],find z.


Solve the equation \[\left| z \right| = z + 1 + 2i\].


What is the smallest positive integer n for which \[\left( 1 + i \right)^{2n} = \left( 1 - i \right)^{2n}\] ?


If z1z2z3 are complex numbers such that \[\left| z_1 \right| = \left| z_2 \right| = \left| z_3 \right| = \left| \frac{1}{z_1} + \frac{1}{z_2} + \frac{1}{z_3} \right| = 1\] then find the value of \[\left| z_1 + z_2 + z_3 \right|\] .


If π < θ < 2π and z = 1 + cos θ + i sin θ, then write the value of \[\left| z \right|\] .


If n is any positive integer, write the value of \[\frac{i^{4n + 1} - i^{4n - 1}}{2}\].


Write the argument of −i.


Find the principal argument of \[\left( 1 + i\sqrt{3} \right)^2\] .


If \[\left| z - 5i \right| = \left| z + 5i \right|\] , then find the locus of z.


Write the sum of the series \[i + i^2 + i^3 + . . . .\] upto 1000 terms.


If n ∈ \[\mathbb{N}\] then find the value of \[i^n + i^{n + 1} + i^{n + 2} + i^{n + 3}\] .


If\[z = \cos\frac{\pi}{4} + i \sin\frac{\pi}{6}\], then


The principal value of the amplitude of (1 + i) is


\[(\sqrt{- 2})(\sqrt{- 3})\] is equal to


The argument of \[\frac{1 - i\sqrt{3}}{1 + i\sqrt{3}}\] is


If \[z = \frac{1}{1 - cos\theta - i sin\theta}\] then Re (z) =


If θ is the amplitude of \[\frac{a + ib}{a - ib}\] , than tan θ =


If z is a complex numberthen


Which of the following is correct for any two complex numbers z1 and z2?

 


If the complex number \[z = x + iy\] satisfies the condition \[\left| z + 1 \right| = 1\], then z lies on


Simplify : `sqrt(-16) + 3sqrt(-25) + sqrt(-36) - sqrt(-625)`


Simplify : `4sqrt(-4) + 5sqrt(-9) - 3sqrt(-16)`


Find a and b if `1/("a" + "ib")` = 3 – 2i


Find a and b if (a + ib) (1 + i) = 2 + i


Express the following in the form of a + ib, a, b ∈ R, i = `sqrt(−1)`. State the values of a and b:

(1 + 2i)(– 2 + i)


Express the following in the form of a + ib, a, b∈R i = `sqrt(−1)`. State the values of a and b:

(1 + i)−3 


If z1 and z2 both satisfy `z + barz = 2|z - 1|` arg`(z_1 - z_2) = pi/4`, then find `"Im" (z_1 + z_2)`.


If `((1 - i)/(1 + i))^100` = a + ib, then find (a, b).


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×