मराठी

If y = P eax + Q ebx, show that dy/dx^2=(a+b)dy/dx + aby=0

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प्रश्न

If y = P eax + Q ebx, show that

`(d^y)/(dx^2)=(a+b)dy/dx+aby=0`

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उत्तर

y = P eax + Q ebx

Differentiating w.r.t x, we get:

`dy/dx=Pae^(ax)+Qbe^(bx)..................(1)`

`(a+b)dy/dx=(a+b)(Pae^(ax)+Qbe^(bx))`

`(a+b)dy/dx=Pa^2e^(ax)+Qb^2e^(bx)+ab(Pe^(ax)+Qe^(bx))`

`(a+b)dy/dx=Pa^2e^(ax)+Qb^2e^(bx)+aby`

`-[-(a+b)dy/dx+aby]=Pa^2e^(ax)+Qb^2e^(bx)........(2)`

Differentiating (1) w.r.t. x, we get:

`(d^y)/(dx^2)=Pa^2e^(ax)+Qb^2e^(bx)................(3)`

Subtracting (2) from (3), we get:

`(d^y)/(dx^2)-(a+b)dy/dx+aby=Pa^2e^(ax)+Qb^2e^(bx)-Pa^2e^(ax)-Qb^2e^(bx)`

`(d^y)/(dx^2)-(a+b)dy/dx+aby=0`

Hence proved.

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2013-2014 (March) All India Set 1

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