मराठी

If the Quadrilateral Formed by Joining the Mid-points of the Adjacent Sides of Quadrilateral Abcd is a Rectangle, Show that the Diagonals Ac and Bd Intersect at Right Angle.

Advertisements
Advertisements

प्रश्न

If the quadrilateral formed by joining the mid-points of the adjacent sides of quadrilateral ABCD is a rectangle,
show that the diagonals AC and BD intersect at the right angle.

बेरीज
Advertisements

उत्तर

The figure is shown below

Let ABCD be a quadrilateral where P, Q, R, S are the midpoint of AB, BC, CD, DA.PQRS is a rectangle. Diagonal AC and BD intersect at point O. We need to show that AC and BD intersect at a right angle.

Proof:
PQ || AC, therefore ∠AOD = ∠PXO     ...[ Corresponding angle ]...(1)

Again BD || RQ, therefore ∠PXO = ∠RQX = 90°  ....[ Corresponding angle and angle of a rectangle ]...(2)

From (1) and (2) we get ,
∠AOD = 90°

Similarly, ∠AOB = ∠BOC = ∠DOC = 90°
Therefore diagonals AC and BD intersect at right angle.
Hence proved.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 11: Mid-point Theorem and Its Converse [Including Intercept Theorem] - Exercise 12 (B) [पृष्ठ १५४]

APPEARS IN

सेलिना Concise Mathematics [English] Class 9 ICSE
पाठ 11 Mid-point Theorem and Its Converse [Including Intercept Theorem]
Exercise 12 (B) | Q 9 | पृष्ठ १५४

संबंधित प्रश्‍न

ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see the given figure). AC is a diagonal. Show that:

  1. SR || AC and SR = `1/2AC`
  2. PQ = SR
  3. PQRS is a parallelogram.


ABC is a triangle right angled at C. A line through the mid-point M of hypotenuse AB and parallel to BC intersects AC at D. Show that

  1. D is the mid-point of AC
  2. MD ⊥ AC
  3. CM = MA = `1/2AB`

ABCD is a kite having AB = AD and BC = CD. Prove that the figure formed by joining the
mid-points of the sides, in order, is a rectangle.


D, E, and F are the mid-points of the sides AB, BC and CA of an isosceles ΔABC in which AB = BC.

Prove that ΔDEF is also isosceles.


In trapezium ABCD, AB is parallel to DC; P and Q are the mid-points of AD and BC respectively. BP produced meets CD produced at point E.

Prove that:

  1. Point P bisects BE,
  2. PQ is parallel to AB.

In a right-angled triangle ABC. ∠ABC = 90° and D is the midpoint of AC. Prove that BD = `(1)/(2)"AC"`.


In ΔABC, P is the mid-point of BC. A line through P and parallel to CA meets AB at point Q, and a line through Q and parallel to BC meets median AP at point R. Prove that: AP = 2AR


E is the mid-point of the side AD of the trapezium ABCD with AB || DC. A line through E drawn parallel to AB intersect BC at F. Show that F is the mid-point of BC. [Hint: Join AC]


E is the mid-point of a median AD of ∆ABC and BE is produced to meet AC at F. Show that AF = `1/3` AC.


Show that the quadrilateral formed by joining the mid-points of the consecutive sides of a square is also a square.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×