मराठी

If sinθ + cosθ = 1, then find the general value of θ.

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प्रश्न

If sinθ + cosθ = 1, then find the general value of θ.

बेरीज
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उत्तर

Given, sinθ + cosθ = 1

On dividing both the sides by `sqrt2`,

`sintheta/sqrt2 + costheta/sqrt2 = 1/sqrt2`

⇒ `cos(theta - pi/4) = cos  pi/4`

⇒ `theta - pi/4 = pi/4`

We know that, θ = 2nπ ± α when cosθ = cosα

⇒ `theta - pi/4 = 2npi ± pi/4, n ∈ z`

⇒ `theta = 2npi ± pi/4 + pi/4`

Taking the positive sign,

⇒ `theta = 2npi + pi/4 + pi/4`

⇒ `theta = 2npi + pi/2`

Taking the Negative sign,

⇒ `theta = 2npi - pi/4 + pi/4`

⇒ θ = 2nπ, n ∈ z

So, the general value is `theta = 2npi + pi/2` and θ = 2nπ.

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पाठ 3: Trigonometric Functions - Exercise [पृष्ठ ५३]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
पाठ 3 Trigonometric Functions
Exercise | Q 15 | पृष्ठ ५३

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