मराठी

Show that 2 sin2β + 4 cos (α + β) sin α sin β + cos 2(α + β) = cos 2α

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प्रश्न

Show that 2 sin2β + 4 cos (α + β) sin α sin β + cos 2(α + β) = cos 2α

बेरीज
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उत्तर

L.H.S = 2 sin2 β + 4 cos (α + β) sin α sin β + cos 2(α + β)

= 2 sin2β + 4(cos α cos β – sin α sin β) sin α sin β + (cos 2α cos 2β – sin 2α sin 2β)

= 2 sin2β + 4 sin α cos α sin β cos β – 4 sin2α sin2β + cos 2α cos 2β – sin 2α sin 2β

= 2 sin2 β + sin 2α sin 2β – 4 sin2α sin2β + cos 2α cos 2β – sin 2α sin 2β

= (1 – cos 2β) – (2 sin2α) (2 sin2β) + cos 2α cos 2β

= (1 – cos 2β) – (1 – cos 2α) (1 – cos 2β) + cos 2α cos 2β 

= cos 2α = R.H.S. 

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पाठ 3: Trigonometric Functions - Solved Examples [पृष्ठ ४६]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
पाठ 3 Trigonometric Functions
Solved Examples | Q 12 | पृष्ठ ४६

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