मराठी

If Cos (A − B) = 3 5 and Tan a Tan B = 2, Then

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प्रश्न

If cos (A − B) \[= \frac{3}{5}\] and tan A tan B = 2, then

पर्याय

  • \[\cos A \cos B = \frac{1}{5}\]

     

  • \[\cos A \cos B = - \frac{1}{5}\]

     

  • \[\sin A \sin B = - \frac{1}{5}\]

     

  • \[\sin A \sin B = - \frac{1}{5}\]

     

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उत्तर

\[\frac{1}{5}\]

\[\tan A \tan B=\frac{\sin A \sin B}{\cos A \cos B}=2 \left( \text{Given }\right) . . . (1)\]

Also,
\[\cos(A - B) = \frac{3}{5}\]
\[ \Rightarrow \cos A \cos B + \sin A \sin B = \frac{3}{5}\]

\[\therefore \sin A \sin B = \frac{3}{5} - \cos A\cos B . . . (2) \]
\[\text{ Substituting eq (2) in eq (1), we get:}\]

\[\Rightarrow \frac{\frac{3}{5} - \cos A \cos B}{\cos A \cos B}=2\]
\[\Rightarrow 3\cos A \cos B= \frac{3}{5}\]
\[\Rightarrow \cos A \cos B=\frac{1}{5}\]
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पाठ 7: Values of Trigonometric function at sum or difference of angles - Exercise 7.4 [पृष्ठ २८]

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आर.डी. शर्मा Mathematics [English] Class 11
पाठ 7 Values of Trigonometric function at sum or difference of angles
Exercise 7.4 | Q 21 | पृष्ठ २८

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