मराठी

If Cos a + Sin B = M and Sin a + Cos B = N, Prove that 2 Sin (A + B) = M2 + N2 − 2.

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प्रश्न

If cos A + sin B = m and sin A + cos B = n, prove that 2 sin (A + B) = m2 + n2 − 2.

 
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उत्तर

\[\text{ RHS }= m^2 + n^2 - 2\]
\[ = \left( \cos A + \sin B \right)^2 + \left( \sin A + \cos B \right)^2 - 2\]
\[ = \cos^2 A + \sin^2 B + 2\cos A\sin B + \sin^2 A + \cos {}^2 B + 2\sin A\cos B - 2\]
\[ = 1 + 1 + 2\cos A\sin B + 2\sin A\cos B - 2\]
\[ = 2\left( \cos A\sin B + \sin A \cos B \right)\]
\[ = 2\sin\left( A + B \right)\]
 = LHS
Hence proved.

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पाठ 7: Values of Trigonometric function at sum or difference of angles - Exercise 7.1 [पृष्ठ २०]

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आर.डी. शर्मा Mathematics [English] Class 11
पाठ 7 Values of Trigonometric function at sum or difference of angles
Exercise 7.1 | Q 22 | पृष्ठ २०

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