मराठी

The value of sin(45° + θ) - cos(45° - θ) is ______.

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प्रश्न

The value of sin(45° + θ) - cos(45° - θ) is ______.

पर्याय

  • 2cosθ

  • 2sinθ

  • 1

  • 0

MCQ
रिकाम्या जागा भरा
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उत्तर

The value of sin(45° + θ) - cos(45° - θ) is 0.

Explanation:

Given expression is sin(45° + θ) - cos(45° - θ)

sin(45° + θ) = sin45° cosθ + cos45° sinθ

= `1/sqrt(2) cos theta + 1/sqrt(2) sin theta`

cos(45° - θ) = cos45° cosθ + sin45° sinθ

= `1/sqrt(2) cos theta + 1/sqrt(2) sin theta`

sin(45° + θ) - cos(45° - θ)

= `1/sqrt(2) costheta + 1/sqrt(2) sintheta - 1/sqrt(2) cos theta - 1/sqrt(2) sin theta`

= 0.

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पाठ 3: Trigonometric Functions - Exercise [पृष्ठ ५७]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
पाठ 3 Trigonometric Functions
Exercise | Q 43 | पृष्ठ ५७

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