मराठी

Prove that: sin 3x + sin 2x – sin x = 4sin x cos x2cos 3x2

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प्रश्न

Prove that: sin 3x + sin 2x – sin x = 4sin x `cos  x/2 cos  (3x)/2`

बेरीज
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उत्तर

L.H.S. = sin 3x + (sin 2x – sin x)

= `2sin  (3x)/2  cos  (3x)/2 + 2  cos  (2x + x)/2  sin  (2x - x)/2`   `[∵ sin A = 2sin  A/2  cos  A/2]`

= `2 sin  (3x)/2  cos  (3x)/2  +2cos  (3x)/2  sin  (x)/2` 

= `2cos   (3x)/2 [sin  (3x)/2 + sin  x/2 ]`

=  `2cos   (3x)/2 [(2sin  (3x)/2 + x/2)/2  (cos  (3x)/2 - x/2)/2]`

= `2cos  (3x)/3 [2sin x cos  x/2]`

= `4 sin x cos  x/2 cos  (3x)/2` 

=  R.H.S.

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पाठ 3: Trigonometric Functions - Miscellaneous Exercise [पृष्ठ ७२]

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एनसीईआरटी Mathematics [English] Class 11
पाठ 3 Trigonometric Functions
Miscellaneous Exercise | Q 7. | पृष्ठ ७२

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