मराठी

If θ is the angle between two vectors a→ and b→, then a→.b→≥0 only when ______.

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प्रश्न

If θ is the angle between two vectors `veca` and `vecb`, then `veca . vecb >= 0` only when ______.

पर्याय

  • `0 < θ < pi/2`

  • `0 ≤ θ ≤ pi/2`

  • `0 < θ < pi`

  • `0 ≤ θ ≤ pi`

MCQ
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उत्तर

If θ is the angle between two vectors `veca` and `vecb`, then `veca . vecb >= 0` only when `underline(0 ≤ θ ≤ pi/2)`.

Explanation:

Let θ be the angle between two vectors, `veca` and `vecb`.

Then, without loss of generality, `veca`,`vecb` are non zero vectors so that `|veca|,|vecb|` are positive

It is known that `veca × vecb = |veca||vecb|cosθ`

a × b ≥ 0

`|veca||vecb|cosθ≥0`

cosθ ≥ 0

`0 ≤ θ ≤ (π/2)`

So, a × b ≥ 0 when `0 ≤ θ ≤ (π/2).`

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Vector Algebra - Exercise 10.5 [पृष्ठ ४५९]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 10 Vector Algebra
Exercise 10.5 | Q 16 | पृष्ठ ४५९

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