Advertisements
Advertisements
प्रश्न
How would you set up a circuit to obtain NOT gate using a transistor?
Advertisements
उत्तर
(1) It has only one input and only one output.
(2) Boolean expression is Y = Ᾱ and is read as “y equals not A”.
Logical symbol of NOT gate.

(3) Realization of NOT gate: The transistor is so biased that the collector voltage VCC = V (Voltage corresponding to 1 state)
The resistors R and RB are so chosen that if the input is low, i.e. 0, the transistor is in the cut-off and hence the voltage appearing at the output will be the same as applied V = 5 V. Hence Y = V (or state I)
If the input is high, the transistor current is in saturation and the net voltage at the output Y is 0 (in state 0).

(4) Truth table for NOT gate:
| A | Y = Ā |
| 0 | 1 |
| 1 | 0 |
APPEARS IN
संबंधित प्रश्न
Which logic gate corresponds to the truth table given below?
|
A |
B |
Y |
|
0 |
0 |
I |
|
0 |
1 |
0 |
|
1 |
0 |
0 |
|
1 |
1 |
0 |
Write the truth table for a NAND gate connected as given in the following figure.

Hence identify the exact logic operation carried out by this circuit
Write the truth table for circuit given in figure below consisting of NOR gates and identify the logic operation (OR, AND, NOT) which this circuit is performing.

(Hint: A = 0, B = 1 then A and B inputs of second NOR gate will be 0 and hence Y=1. Similarly work out the values of Y for other combinations of A and B. Compare with the truth table of OR, AND, NOT gates and find the correct one.)
Draw the schematic symbols for AND, OR, NOT and NAND gate
The following figure shows the input waveforms (A, B) and the output waveform (Y) of a gate. Identify the gate, write its truth table and draw its logic symbol.

What will be the values of input A and B for the Boolean expression `overline ((A +B) .(A*B)) =1?`
Let \[X = A \overline{ BC} + B\overline{ CA} + C\overline{AB } .\] Evaluate X for A = 1, B = 0, C = 1.
Show that \[AB + \overline {AB }\] is always 1.
Why are NOR gates considered as universal gates?
Draw a diagram to show how NAND gates can be combined to obtain an OR gate. (Truth table is not, required)
Useful Constants and Relations:
| 1. | Charge of a proton | (e) | =1.6 × 10-19C |
| 2. | Planck's constant | (h) | = 6·6 × 10-34 Js |
| 3. | Mass of an electron | (m) | = 9·1× 10-31 kg |
| 4. | Permittivity of vacuum | (∈0) | =8 · 85 × 10-12 Fm-1 |
| 5. | `(1/(4pi∈_0))` | =9 ×109 mF-1 | |
| 6. | Permeability of vacuum | (μ0) | = 4π × 10-7 Hm-1 |
| 7. | `((mu_0)/(4pi))` | =1 × 10-7 Hm-1 | |
| 8. | Speed of light in vacuum | (c) | = 3× 108 ms-1 |
| 9. | Unified atomic mass unit | (u) |
= 931 MeV |
| 10. | Electron volt | (leV) | = 1.6 × 10-19 J |
With the help of a diagram, show how you can use several NAND gates to obtain an OR gate.
Useful Constants and Relations :
| 1. Speed of Light in Vacuum | (c) = 3.00 x 108 m/s |
| 2. Charge of a proton | (e) = 1.60 x 10-19C |
| 3. Planck's Constant | (h) = 6.6 x 10-34 Js |
| 4. Permeability of vacuum | (μ0) = 4π x 10-7 Hm-1 |
| 5. Electron Volt | (1eV ) = 1.6 x 10 |
| 6. Unified Atomic Mass Unit | (1u) = 931 MeV |
| (π) = 3.14 | |
| ( ln 2 ) = 0.693 |
The outputs of two NOT gates are fed to a NOR gate. Draw the logic circuit of the combination of gates. Write its truth table. Identify the gate equivalent to this circuit.
The current obtained from a simple filterless rectifier is
In potential barrier development in a junction diode opposes
The truth table for the following logic circuit is:

Truth table for the given circuit (Figure) is ______.

Write the truth table for the circuit shown in figure. Name the gate that the circuit resembles.

A logic gate circuit has two inputs A and B and output Y. The voltage waveforms of A, B and Y are shown below.

The logic gate circuit is ______.
