Advertisements
Advertisements
प्रश्न
Give simple chemical tests to distinguish between the following pair of compounds:
Benzaldehyde and Benzoic acid
Give simple chemical test to distinguish between Benzoic acid and Benzaldehyde.
Advertisements
उत्तर १
Through sodium bicarbonate:
Benzaldehyde does not react with sodium bicarbonate. However, benzoic acid will produce brisk effervescence in reaction with sodium bicarbonate, as shown in the given reaction:
\[\ce{C6H5COOH + NaHCO3 -> C6H5COO^-Na+ + CO2 ↑ + H2O}\]
\[\ce{C6H5CHO ->[NaHCO3 solution] No effervescene}\]
Through Tollen's reagent:
Benzaldehyde reacts with an ammonia solution of silver nitrate to form a silver mirror.
\[\ce{C6H5CHO + 2[Ag(NH3)2]+ + 3OH^- -> C6H5COO^- + 2Ag + 2H2O + 4NH3}\]
However, no such reaction is given by benzoic acid.
उत्तर २
Benzoic acid reacts with ethanol in the presence of dilute sulphuric acid to form sweet-smelling ester Ethyl benzoate. This reaction is not given by benzaldehyde.
Notes
Students can refer to the provided solutions based on their preferred marks.
APPEARS IN
संबंधित प्रश्न
Write the IUPAC name of the following compound and classify it as primary, secondary and tertiary amine.
CH3(CH2)2NH2
Write the IUPAC name of the following compound and classify it as primary, secondary and tertiary amine.
(CH3CH2)2NCH3
Give one chemical test to distinguish between the following pair of compounds.
Methylamine and dimethylamine
Give one chemical test to distinguish between the following pair of compounds.
Ethylamine and aniline
Give one chemical test to distinguish between the following pair of compounds.
Aniline and N-methylaniline
How will you convert hexanenitrile into 1-aminopentane?
Accomplish the following conversion:
Aniline to benzyl alcohol
What is the action of p-toluenesulphonychloride on ethylamine and diethylamine?
Using IUPAC norms, write the formula of Hexaamminecobalt(III) sulphate.
Do the following conversions in not more than two steps:
\[\begin{array}{cc}
\ce{CH3CN to CH3 - C - CH3}\\
\phantom{...........}||\\
\phantom{...........}\ce{O}
\end{array}\]
