मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Give a simple chemical test to distinguish between the following pair of compounds: Propanal and Propanone

Advertisements
Advertisements

प्रश्न

Give a simple chemical test to distinguish between the following pair of compounds:

Propanal and Propanone

Give a chemical test to distinguish between propanal and propanone.

Give a simple chemical test to distinguish between propanal and propanone.

रासायनिक समीकरणे/रचना
फरक स्पष्ट करा
Advertisements

उत्तर १

Propanal and propanone can be distinguished by the following tests:

  1. Tollen’s test: Propanal is an aldehyde. Thus, it reduces Tollen’s reagent. But, propanone being a ketone does not reduce Tollen’s reagent.
    \[\ce{\underset{Propanal}{CH3CH2CHO} + \underset{Tollen's reagent}{2[Ag(NH3)2]+} + 3OH- -> \underset{Propanoate ion}{CH3CH2COO-} + \underset{Silver mirror}{Ag\downarrow} + NH3 + 2H2O}\]
  2. Fehling’s test: Aldehydes respond to Fehling’s test, but ketones do not. Propanal, being an aldehyde reduces Fehling’s solution to a red-brown precipitate of Cu2O, but propanone being a ketone does not.
    \[\ce{\underset{Propanal}{CH3CH2CHO} + 2Cu^2+ + 5OH- -> \underset{Propanoate ion}{CH3CH2COO-} + \underset{(Red-brown ppt)}{\underset{Cuprous oxide}{Cu2O\downarrow}}+ 2H2O}\]
  3. Iodoform test: Aldehydes and ketones with at least one methyl group linked to the carbonyl carbon atom respond to the iodoform test. They are oxidized by sodium hypoiodite (NaOI) to give iodoforms. Propanone being a methyl ketone responds to this test, but propanal does not.
    \[\ce{\underset{Propanone}{CH3COCH3} + 3NaOI -> \underset{Sodium acetate}{CH3COONa} + \underset{(yellow ppt)}{\underset{Iodoform}{CHI3}}+  2NaOH}\]
shaalaa.com

उत्तर २

Reagent Propanal Propanone
Tollen’s Reagent On heating with Tollen’s reagent, a silver mirror is formed on the inner walls of the test tube. Aldehyde groups reduce the Tollen’s reagent. On heating in a water bath with Tollen’s reagent does not show any reaction.
shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Aldehydes, Ketones and Carboxylic Acids - Exercises [पृष्ठ २५६]

संबंधित प्रश्‍न

Give a simple chemical test to distinguish between the following pair of compounds:

Ethanal and Propanal


Distinguish between:

C6H5-COCH3 and C6H5-CHO


Distinguish between: CH3COOH and HCOOH


Out of CH3CH2 – CO – CH2 – CH3 and CH3CH2 – CH2 – CO – CH3, which gives iodoform test?


Give a simple chemical test to distinguish between the following pair of compounds:

Phenol and Benzoic acid


Alkenes decolourise bromine water in presence of CCl4 due to formation of ______.


Which of the following compounds will give butanone on oxidation with alkaline \[\ce{KMnO4}\] solution?


Which of the following compounds gives a positive Tollen's test but negative Fehling's test?


Ammonical silver nitrate solution is called


Which of the following tests/reactions is given by aldehydes as well as ketones?


A hydrocarbon (A) with molecular formula C5H10 on ozonolysis gives two products (B) and (C). Both (B) and (C) give a yellow precipitate when heated with iodine in presence of NaOH while only (B) give a silver mirror on reaction with Tollen’s reagent.

  1. Identify (A), (B) and (C).
  2. Write the reaction of B with Tollen’s reagent.
  3. Write the equation for iodoform test for C.
  4. Write down the equation for aldol condensation reaction of B and C.

Which among the above compound/s does/do not form Silver mirror when treated with Tollen's reagent?


Choose the reaction which is not possible: 


The reagent that can be used to distinguish acetophenone and benzophenone is ______.


You are given four organic compounds “A”, “B” , “C” and “D”. The compounds “A”, “B” and “C” form an orange-red precipitate with 2, 4 DNP reagent. Compounds “A” and “B” reduce Tollen’s reagent while compounds “C” and “D” do not. Both “B” and “C” give a yellow precipitate when heated with iodine in the presence of NaOH. Compound “D” gives brisk effervescence with sodium bicarbonate solution. Identify “A”, “B”, “C” and “D” given the number of carbon atoms in three of these carbon compounds is three while one has two carbon atoms. Give an explanation for our answer.


Benzaldehyde is obtained from Rosenmund’s reduction of:


Fehling’s solution ‘A’ is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×