Advertisements
Advertisements
प्रश्न
Give reason for the following:
A plant cell, when kept in a hypertonic salt solution for about 30 minutes, turns flaccid.
Advertisements
उत्तर
In a hypertonic solution, the solution outside the cell has a higher solute concentration than the fluids inside the cell. Therefore, water flows out of the plant cell due to exosmosis. The cytoplasm shrinks, the plasma membrane withdraws away from the cell wall and the cell becomes flaccid. Hence, a plant cell, when kept in a hypertonic salt solution for about 30 minutes, turns flaccid.
संबंधित प्रश्न
A plant cell may burst when :
Give the equivalent terms for the following:
Loss of water through a cut stem.
Differentiate between the following:
Turgidity and Flaccidity
Mention whether the following statement is true (T) or false (F) and give an explanation in support of your answer.
Soaked seeds burst into three seed coats.
Differentiate between:
Turgid and Flaccid.
Differentiate between the following:
Plasmolysis and Deplasmolysis.
The below diagram represents a plant cell after being placed in a strong sugar solution. Guidelines 1 to 5 indicate the following:
1. Cell wall
2. Plasma membrane.
3. Protoplasm
4. Large vacuole
5. Nucleus
Study the diagram and answer the questions that follow :
(i) What is the state of the cell shown in the diagram?
(ii) Name the structure which acts as a selectively permeable membrane.
(iii) If the cell had been placed in distilled water instead of a strong sugar solution which features: would not have been present?
(iv) If the cell in the diagram possessed chloroplasts where would these be present?
(v) Name any one feature of this plant cell which is not present in animal cells.
Give Technical Term for the following.
The pressure exerted by cell contents on a plant cell wall.
Multiple Choice Question:
When cell is fully turgid, which of the following will be zero?
Deplasmolysis occurs when a plasmolysed cell is placed in ______.
