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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Give one chemical test to distinguish between the following pair of compounds. Aniline and N-methylaniline

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प्रश्न

Give one chemical test to distinguish between the following pair of compounds.

Aniline and N-methylaniline

रासायनिक समीकरणे/रचना
फरक स्पष्ट करा
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उत्तर

Aniline and N-methylaniline can be distinguished using the Carbylamine test. Primary amines, on heating with chloroform and ethanolic potassium hydroxide, form foul-smelling isocyanides or carbylamines. Aniline, being an aromatic primary amine, gives a positive carbylamine test. However, N-methylaniline, being a secondary amine, does not.

\[\ce{\underset{(Primary amine)}{\underset{Aniline}{C6H5NH2}} + CHCl3 + 3KOH ->[\Delta] \underset{(foul smell)}{\underset{Benzyl isocyanide}{C6H5NC}} + 3KCl + 3H2O}\]

\[\ce{\underset{(Secondary amine)}{\underset{N-methylaniline}{C6H5NHCH3}} + CHCl3 + 3KOH ->[\Delta] No reaction}\]

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पाठ 9: Amines - Exercises [पृष्ठ २७८]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 9 Amines
Exercises | Q 9.2 (v) | पृष्ठ २७८

संबंधित प्रश्‍न

Which among the following molecular formulae represents urotropine?

(a) C6H12N4

(b) C6H24H4                    

(c) C6H12N4O2

(d) C6H24N4O2


Write the IUPAC name of the following compound and classify it as primary, secondary and tertiary amine.

CH3(CH2)2NH2


Write the IUPAC name of the following compound and classify it as primary, secondary and tertiary amine.

(CH3)3CNH2


Write the IUPAC name of the following compound and classify it as primary, secondary and tertiary amine.

m−BrC6H4NH2


Account for the following:

pKb of aniline is more than that of methylamine.


Account for the following:

Ethylamine is soluble in water, whereas aniline is not.


Account for the following:

Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.


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Complete the following reaction:

\[\ce{C6H5NH2 + H2SO4 (conc.)}\]


Complete the following reaction:

\[\ce{C6H5NH2 + Br2 (aq) ->}\]


Complete the following reaction:

\[\ce{C6H5NH2 + (CH3CO)2O ->}\]


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Propanone to Propene


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