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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Find the general solution of the following equation: sinθ = 12.

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प्रश्न

Find the general solution of the following equation:

sinθ = `1/2`.

बेरीज
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उत्तर

The general solution of sin θ = sin α is 
θ = nπ + (– 1)nα, n ∈ Z

Now,
`sinθ = 1/2 = sin  π/6     ...[∵ sin  pi/(6) = 1/2]`

∴ the required general solution is θ = nπ + (– 1)n `π/6`, n ∈ Z.

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पाठ 3: Trigonometric Functions - Exercise 3.1 [पृष्ठ ७५]

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