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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Find the equation of the ellipse in standard form if the latus rectum has length of 6 and foci are (±2, 0).

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प्रश्न

Find the equation of the ellipse in standard form if the latus rectum has length of 6 and foci are (±2, 0).

बेरीज
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उत्तर

Let the equation of the ellipse be

`x^2/"a"^2 + y^2/"b"^2` = 1    ...(1)

Then length of latus rectum = `(2"b"^2)/"a"`

and foci = (±ae, 0)

∴ `(2"b"^2)/"a"` = 6  ...(2)

ae = 2  ...(3)

∵ b2 = a2 (1 – e2), from (2),

`(2"a"^2(1 - "e"^2))/"a"` = 6

∴ (a2 – a2e2) = 3a

∴ a2 – 4 = 3a  ....[By (3)]

∴ a2 – 3a – 4 = 0

∴ (a – 4)(a + 1) = 0

∴ a = 4 or a = – 1

But a ≠ – 1

∴ a = 4

∴ from (2), `(2"b"^2)/4` = 6

∴ b2 = 12

∴ from (1), the equation of the required ellipse is

`x^2/16 + y^2/12` = 1

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पाठ 7: Conic Sections - Exercise 7.2 [पृष्ठ १६३]

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