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प्रश्न
Find the energy of photon which have momentum 2 × 10-16 gm-cm/sec.
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उत्तर
Given, P = `2 × 10^(−16)` gm−cm/sec; c = 3 × 1010 cm/sec
E = pc
= 2 × 10−16 × 3 × 1010
= 6 × 10–6 erg
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संबंधित प्रश्न
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(i) if ultraviolet radiation of wavelength λ = 1.80 × 10-5 cm and
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| Incident wavelength (in Å) | 2536 | 3650 |
| Stopping potential (in V) |
1.95 | 0.5 |
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