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प्रश्न
Find the class-mark of the class 35 - 40.
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उत्तर
Class mark = `("Lower class limit" + "Upper class limit")/2`
Since, `(35 + 40)/2`
= `75/2`
= 37.5
So, the class mark for the class 35 - 40 is 37.5.
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संबंधित प्रश्न
For class interval 20-25 write the lower class limit and the upper class limit.
In the table given below, class-mark and frequencies are given. Construct the frequency table taking inclusive and exclusive classes.
| Class width | Frequency |
| 5 | 3 |
| 15 | 9 |
| 25 | 15 |
| 35 | 13 |
38 people donated to an organisation working for differently abled persons. The amount in rupees were as follows:
101, 500, 401, 201, 301, 160, 210, 125, 175, 190, 450, 151, 101, 351, 251, 451, 151, 260, 360, 410, 150, 125, 161, 195, 351, 170, 225, 260, 290, 310, 360, 425, 420, 100, 105, 170, 250, 100.
- By taking classes 100-149, 150-199, 200-249... prepare grouped frequency distribution table.
- From the table, find the number of people who donated rupees 350 or more.
The value of π up to 50 decimal place is
3.14159265358979323846264338327950288419716939937510
(i) Make a frequency distribution table of digits from 0 to 9 after the decimal place.
(ii) Which are the most and least occurring digits?
Given below are the marks obtained by 30 students in an examination:
| 08 | 17 | 33 | 41 | 47 | 23 | 20 | 34 |
| 09 | 18 | 42 | 14 | 30 | 19 | 29 | 11 |
| 36 | 48 | 40 | 24 | 22 | 02 | 16 | 21 |
| 15 | 32 | 47 | 44 | 33 | 01 |
Taking class intervals 1-10, 11-20, ....., 41-50; make a frequency table for the above distribution.
Construct the frequency distribution table from the following cumulative frequency table:
| Ages | No. of students |
| Below 4 | 0 |
| Below 7 | 85 |
| Below 10 | 140 |
| Below 13 | 243 |
| Below 16 | 300 |
(i) State the number of students in the age group 10 - 13.
(ii) State the age-group which has the least number of students.
Construct a frequency table from the following data:
| Marks | No. of students |
| less than 10 | 6 |
| less than 20 | 15 |
| less than 30 | 30 |
| less than 40 | 39 |
| less than 50 | 53 |
| less than 60 | 70 |
Construct a cumulative frequency distribution table from the frequency table given below:
( i )
| Class Interval | Frequency |
| 0 - 8 | 9 |
| 8 - 16 | 13 |
| 16 - 24 | 12 |
| 24 - 32 | 7 |
| 32 - 40 | 15 |
( ii )
| Class Interval | Frequency |
| 1 - 10 | 12 |
| 11 - 20 | 18 |
| 21 - 30 | 23 |
| 31 - 40 | 15 |
| 41 - 50 | 10 |
Construct a cumulative frequency distribution table from the frequency table given below:
| Class Interval | Frequency |
| 0 -8 | 9 |
| 8 - 16 | 13 |
| 16 - 24 | 12 |
| 24 - 32 | 7 |
| 32 - 40 | 15 |
Given below are the marks obtained by 30 students in an examination:
|
08 |
17 |
33 |
41 |
47 |
23 |
20 |
34 |
|
09 |
18 |
42 |
14 |
30 |
19 |
29 |
11 |
|
36 |
48 |
40 |
24 |
22 |
02 |
16 |
21 |
|
15 |
32 |
47 |
44 |
33 |
01 |
Taking class intervals 1 - 10, 11 - 20, ....., 41 - 50; make a frequency table for the above distribution.
The height of 30 children in a class is given in centimetres. Draw up a frequency table of this data.
131, 135, 140, 138, 132, 133, 135, 133, 134, 135, 132, 133, 140, 139, 132, 131, 134, 133, 140, 140, 139, 136, 137, 136, 139, 137, 133, 134, 131, 140
In a certain colony, there are 50 families. The number of people in every family is given below. Draw up the frequency table.
5, 4, 5, 4, 5, 3, 3, 3, 4, 3, 4, 2, 3, 4, 2, 2, 2, 2, 4, 5, 1, 3, 2, 4, 5, 3, 3, 2, 4, 4, 2, 3, 4, 3, 4, 2, 3, 4, 5, 3, 2, 3, 2, 3, 4, 5, 3, 2, 3, 2
A dice was cast 40 times and each score noted is given below. Draw up a frequency table for this data.
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Tally marks are used to find ______.
The difference between the upper and lower limit of a class interval is called the ______ of the class interval.
In the class intervals 10 – 20, 20 – 30, etc., respectively, 20 lies in the class ______.
Using the following frequency table.
| Marks (obtained out of 10) | 4 | 5 | 7 | 8 | 9 | 10 |
| Frequency | 5 | 10 | 8 | 6 | 12 | 9 |
The frequency of more than 8 marks is 21.
Following are the number of members in 25 families of a village:
6, 8, 7, 7, 6, 5, 3, 2, 5, 6, 8, 7, 7, 4, 3, 6, 6, 6, 7, 5, 4, 3, 3, 2, 5.
Prepare a frequency distribution table for the data using class intervals 0 – 2, 2 – 4, etc.
Complete the following table:
| Weights (in kg.) |
Tally Marks | Frequency (Number of persons) |
| 40 – 50 | `\cancel(bb|bb|bb|bb|) \cancel(bb|bb|bb|bb|) bb|bb|` | |
| 50 – 60 | `\cancel(bb|bb|bb|bb|) \cancel(bb|bb|bb|bb|) bb|bb|bb|bb|` | |
| 60 – 70 | `\cancel(bb|bb|bb|bb|) bb|` | |
| 70 – 80 | `bb|bb|` | |
| 80 – 90 | `bb|` |
Find the total number of persons whose weights are given in the above table.
