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प्रश्न
Form a continuous frequency distribution table for the marks obtained by 30 students in a X std public examination.
328, 470, 405, 375, 298, 326, 276, 362, 410, 255, 391, 370, 455, 229, 300, 183, 283, 366, 400, 495, 215, 157, 374, 306, 280, 409, 321, 269, 398, 200
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उत्तर
Maximum mark obtained = 495
Minimum marks obtained = 157
Range = Maximum value – Minimum value
Range = 495 – 157
= 338
If we take the class size as 50 then the number of class intervals possible
= `"Range"/"Class size"`
= `338/50`
= 6.76 ≅ 7
| Class Intervals | Tally marks | Frequency |
| 150 - 200 | || | 2 |
| 200 - 250 | ||| | 3 |
| 250 - 300 | |||| | | 6 |
| 300 - 350 | |||| | 5 |
| 350 - 400 | |||| || | 7 |
| 400 - 450 | |||| | 4 |
| 450 - 500 | ||| | 3 |
| Total | 30 | |
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संबंधित प्रश्न
Complete the Following Table.
| Classes (age) | Tally marks | Frequency (No. of students) |
| 12 - 13 | `cancel(bb|bb|bb|bb|)` | `square` |
| 13 - 14 | `cancel(bb|bb|bb|bb|)` `cancel(bb|bb|bb|bb|)` `bb|bb|bb|bb|` | `square` |
| 14 - 15 | `square` | |
| 15 - 16 | `bb|bb|bb|bb|` | `square` |
| `bb(N = sumf = 35)` |
38 people donated to an organisation working for differently abled persons. The amount in rupees were as follows:
101, 500, 401, 201, 301, 160, 210, 125, 175, 190, 450, 151, 101, 351, 251, 451, 151, 260, 360, 410, 150, 125, 161, 195, 351, 170, 225, 260, 290, 310, 360, 425, 420, 100, 105, 170, 250, 100.
- By taking classes 100-149, 150-199, 200-249... prepare grouped frequency distribution table.
- From the table, find the number of people who donated rupees 350 or more.
If the classes are 0-10, 10-20, 20-30... then in which class should the observation 10 be included?
Fill in the blank in the following table:
| Class interval | Frequency | Cumulative Frequency |
| 25 - 34 | ...... | 15 |
| 35 - 44 | ...... | 28 |
| 45 - 54 | 21 | ...... |
| 55 - 64 | 16 | ...... |
| 65 - 74 | ...... | 73 |
| 75 - 84 | 12 | ...... |
Construct the frequency distribution table from the following cumulative frequency table:
| Ages | No. of students |
| Below 4 | 0 |
| Below 7 | 85 |
| Below 10 | 140 |
| Below 13 | 243 |
| Below 16 | 300 |
(i) State the number of students in the age group 10 - 13.
(ii) State the age-group which has the least number of students.
Construct a cumulative frequency distribution table from the frequency table given below:
( i )
| Class Interval | Frequency |
| 0 - 8 | 9 |
| 8 - 16 | 13 |
| 16 - 24 | 12 |
| 24 - 32 | 7 |
| 32 - 40 | 15 |
( ii )
| Class Interval | Frequency |
| 1 - 10 | 12 |
| 11 - 20 | 18 |
| 21 - 30 | 23 |
| 31 - 40 | 15 |
| 41 - 50 | 10 |
Given below are the marks obtained by 30 students in an examination:
|
08 |
17 |
33 |
41 |
47 |
23 |
20 |
34 |
|
09 |
18 |
42 |
14 |
30 |
19 |
29 |
11 |
|
36 |
48 |
40 |
24 |
22 |
02 |
16 |
21 |
|
15 |
32 |
47 |
44 |
33 |
01 |
Taking class intervals 1 - 10, 11 - 20, ....., 41 - 50; make a frequency table for the above distribution.
If a class size is 10 and range is 80 then the number of classes are ___________
Using the following frequency table.
| Marks (obtained out of 10) | 4 | 5 | 7 | 8 | 9 | 10 |
| Frequency | 5 | 10 | 8 | 6 | 12 | 9 |
The frequency of less than 8 marks is 29.
Following are the number of members in 25 families of a village:
6, 8, 7, 7, 6, 5, 3, 2, 5, 6, 8, 7, 7, 4, 3, 6, 6, 6, 7, 5, 4, 3, 3, 2, 5.
Prepare a frequency distribution table for the data using class intervals 0 – 2, 2 – 4, etc.
