Advertisements
Advertisements
प्रश्न
Find the area of a triangle whose sides are 18 cm, 24 cm, and 30 cm. Also, find the length of altitude corresponding to the largest side of the triangle.
Advertisements
उत्तर
Since the sides of the triangle are 18 cm, 24 cm and 30 cm respectively.
s = `(18 + 24 + 30)/(2)`
= 36
Hence the area of the triangle is
A = `sqrt (s( s - a ) ( s - b ) (s -c ))`
= `sqrt (36( 36 - 18 ) ( 36 - 24 ) (36 -30 ))`
= `sqrt (36 xx 18 xx 12 xx 6 )`
= ` sqrt ( 46656 ) `
= 216 sq.cm.
Again
A = `1/2 "base" xx "altitude" `
Hence
216 = `1/2 xx 30 xx h`
h = 14.4cm
APPEARS IN
संबंधित प्रश्न
The area of an equilateral triangle is 36`sqrt3` sq. cm. Find its perimeter.
The base of a triangular field is three times its height. If the cost of cultivating the field at ₹ 36.72 per 100 m2 is ₹ 49,572; find its base and height.
Two sides of a triangle are 6 cm and 8 cm. If the height of the triangle corresponding to 6 cm side is 4 cm; find :
(i) area of the triangle
(ii) height of the triangle corresponding to 8 cm side.
The base and the height of a triangle are in the ratio 4: 5. If the area of the triangle is 40 m2; find its base and height.
The altitude and the base of a triangular field are in the ratio 6: 5. If its cost is ₹ 49,57,200 at the rate of ₹ 36,720 per hectare and 1 hectare = 10,000 sq. m, find (in metre) dimensions of the field.
Use the information given in the adjoining figure to find :
(i) the length of AC.
(ii) the area of an ∆ABC
(iii) the length of BD, correct to one decimal place.

The table given below contains some measures of the triangle. Find the unknown values.
| Side 1 | Side 2 | Side 3 | Perimeter |
| 6 cm | 5 cm | 2 cm | ? |
Find the perimeter and the area of a right angled triangle whose sides are 6 feet, 8 feet and 10 feet
Find the perimeter of An equilateral triangle with side 6 cm
From one vertex of an equilateral triangle with side 40 cm, an equilateral triangle with 6 cm side is removed. What is the perimeter of the remaining portion?
