Advertisements
Advertisements
प्रश्न
Find the area of a triangle whose sides are 18 cm, 24 cm, and 30 cm. Also, find the length of altitude corresponding to the largest side of the triangle.
Advertisements
उत्तर
Since the sides of the triangle are 18 cm, 24 cm and 30 cm respectively.
s = `(18 + 24 + 30)/(2)`
= 36
Hence the area of the triangle is
A = `sqrt (s( s - a ) ( s - b ) (s -c ))`
= `sqrt (36( 36 - 18 ) ( 36 - 24 ) (36 -30 ))`
= `sqrt (36 xx 18 xx 12 xx 6 )`
= ` sqrt ( 46656 ) `
= 216 sq.cm.
Again
A = `1/2 "base" xx "altitude" `
Hence
216 = `1/2 xx 30 xx h`
h = 14.4cm
APPEARS IN
संबंधित प्रश्न
Calculate the area and the height of an equilateral triangle whose perimeter is 60 cm.
ABC is a triangle in which AB = AC = 4 cm and ∠A = 90°. Calculate:
(i) The area of ΔABC,
(ii) The length of the perpendicular from A to BC.
The area of an equilateral triangle is 36`sqrt3` sq. cm. Find its perimeter.
Find the area and the perimeter of quadrilateral ABCD, given below; if AB = 8 cm, AD = 10 cm, BD = 12 cm, DC = 13 cm and ∠DBC = 90°.
The given figure shows a right-angled triangle ABC and an equilateral triangle BCD. Find the area of the shaded portion.

Find the area of a triangle, whose sides are :
10 cm, 24 cm, and 26 cm
The lengths of the sides of a triangle are in the ratio 4: 5 : 3 and its perimeter is 96 cm. Find its area.
Use the information given in the adjoining figure to find :
(i) the length of AC.
(ii) the area of an ∆ABC
(iii) the length of BD, correct to one decimal place.

The perimeter of a triangle is 72cm and its sides are in the ratio 3:4:5. Find its area and the length of the altitude corresponding to the longest side.
Two sides of a triangle are 12 cm and 14 cm. The perimeter of the triangle is 36 cm. What is its third side?
