Advertisements
Advertisements
प्रश्न
A field is in the shape of a quadrilateral ABCD in which side AB = 18 m, side AD = 24 m, side BC = 40m, DC = 50 m and angle A = 90°. Find the area of the field.
Advertisements
उत्तर
Since ∠A = 90°
By Pythagorus Theorem,
In ∆ABD,
Now, the area of ΔABD = `1/2 (18)(24)`
= (18) (12) = 216 m2
In ΔABD
BD = `sqrt("AB"^2 + "AD"^2) = sqrt(18^2 + 24^2)`
= `sqrt(324 + 576) = sqrt(900) = 30`m.
S = `120/20 = 60 cm^2`
=`sqrt( 60xx10xx20xx30)`
= `sqrt(10xx2xx3xx10xx10xx2xx10xx3)`
= 10 × 10 × 6
= 600 cm2
Area of quadrilateral ABCD
= 816cm2
APPEARS IN
संबंधित प्रश्न
If the difference between the sides of a right-angled triangle is 3 cm and its area is 54 cm2; find its perimeter.
The sides of a triangular field are in the ratio 5: 3: 4 and its perimeter is 180 m. Find:
- its area.
- the altitude of the triangle corresponding to its largest side.
- the cost of leveling the field at the rate of Rs. 10 per square meter.
The base and the height of a triangle are in the ratio 4: 5. If the area of the triangle is 40 m2; find its base and height.
Find the area of the right-angled triangle with a hypotenuse of 40 cm and one of the other two sides of 24 cm.
Find the area of a triangle whose base is 3.8 cm and height is 2.8 cm.
Find the area of a right angled triangle whose hypotenuse is 15cm and the base is 9cm.
The table given below contains some measures of the triangle. Find the unknown values.
| Side 1 | Side 2 | Side 3 | Perimeter |
| ? | 8 m | 3 m | 17 m |
Find the perimeter of A scalene triangle with sides 7 m, 8 m, 10 m
Find the perimeter of An isosceles triangle with equal sides 10 cm each and third side is 7 cm
Find the perimeter of An equilateral triangle with side 6 cm
