मराठी

Find the Length of the Perpendicular Drawn from the Point (5, 4, −1) to the Line → R = ^ I + λ ( 2 ^ I + 9 ^ J + 5 ^ K ) . - Mathematics

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प्रश्न

Find the length of the perpendicular drawn from the point (5, 4, −1) to the line \[\overrightarrow{r} = \hat{i}  + \lambda\left( 2 \hat{i} + 9 \hat{j} + 5 \hat{k} \right) .\]

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उत्तर

Let the point (5, 4, -1)   be P and the the point through which the line passes be Q (1, 0, 0).
The line is parallel to the vector  \[\overrightarrow{b} = 2 \hat{i} + 9 \hat{j} + 5 \hat{k} \] 

Now,  \[\overrightarrow{PQ} = - 4 \hat{i} - 4 \hat{j} + \hat{k} \] 

\[\therefore \overrightarrow{b} \times \overrightarrow{PQ} = \begin{vmatrix}\hat{i} & \hat{j}  & \hat{k} \\ 2 & 9 & 5 \\ - 4 & - 4 & 1\end{vmatrix}\]

\[ = 29 \hat{i} - 22 \hat{j} + 28 \hat{k} \]

\[ \Rightarrow \left| \overrightarrow{b} \times \overrightarrow{PQ} \right| = \sqrt{{29}^2 + \left( - 22 \right)^2 + {28}^2}\]

\[ = \sqrt{841 + 484 + 784}\]

\[ = \sqrt{2109}\]

\[\left| \overrightarrow{b} \right| = \sqrt{2^2 + 9^2 + 5^2}\]

\[ = \sqrt{4 + 81 + 25}\]

\[ = \sqrt{110}\]

\[d = \frac{\left| \overrightarrow{b} \times \overrightarrow{PQ} \right|}{\left| \overrightarrow{b} \right|}\]

\[ = \frac{\sqrt{2109}}{\sqrt{110}}\]

\[ = \sqrt{\frac{2109}{110}}\]

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पाठ 28: Straight Line in Space - Exercise 28.4 [पृष्ठ ३०]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 28 Straight Line in Space
Exercise 28.4 | Q 7 | पृष्ठ ३०

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