मराठी

Find the Vector and the Cartesian Equations of the Line that Passes Through the Points (3, −2, −5), (3, −2, 6). - Mathematics

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प्रश्न

Find the vector and the Cartesian equations of the line that passes through the points (3, −2, −5), (3, −2, 6).

 

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उत्तर

Let the line passing through the points, P (3, −2, −5) and Q (3, −2, 6), be PQ.

Since PQ passes through P (3, −2, −5), its position vector is given by,

`veca = 3hati -2hatj - 5hatk`

The direction ratios of PQ are given by,

(3 − 3) = 0, (−2 + 2) = 0, (6 + 5) = 11

The equation of the vector in the direction of PQ is

`vecb = 0.hati - 0.hatj + 11hatk = 11hatk`

The equation of PQ in vector form is given by, `vecr = veca + lambdavecb`, `lambda in R`

`=>vecr = (3hati - 2hatj - 5hatk) + 11lambdahatk`

The equation of PQ in Cartesian form is

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पाठ 11: Three Dimensional Geometry - Exercise 11.1 [पृष्ठ ४७८]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 11 Three Dimensional Geometry
Exercise 11.1 | Q 9 | पृष्ठ ४७८

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