मराठी

By Computing the Shortest Distance Determine Whether the Following Pairs of Lines Intersect Or Not: X − 1 2 = Y + 1 3 = Z a N D X + 1 5 = Y − 2 1 ; Z = 2

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प्रश्न

By computing the shortest distance determine whether the following pairs of lines intersect or not: \[\frac{x - 1}{2} = \frac{y + 1}{3} = z \text{ and } \frac{x + 1}{5} = \frac{y - 2}{1}; z = 2\]

बेरीज
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उत्तर

\[\frac{x - 1}{2} = \frac{y + 1}{3} = \frac{z - 0}{1} and \frac{x + 1}{5} = \frac{y - 2}{1} = \frac{z - 2}{0}\]

Since the first line passes through the point (1, -1, 0) and has direction ratios proportional to 2, 3, 1, its vector equation is

\[\overrightarrow{r} = \overrightarrow{a_1} + \lambda \overrightarrow{b_1} . . . (1) \]

\[\text{ Here } , \]

\[ \overrightarrow{a_1} = \hat{i}  - \hat{j}  + 0 \hat{k}  \]

\[ \overrightarrow{b_1} = 2 \hat{i}  + 3 \hat{j}  + \hat{k} \]

Also, the second line passes through the point ( -1, 2, 2) and has direction ratios proportional to 5, 1, 0. Its vector equation is

\[\overrightarrow{r} = \overrightarrow{a_2} + \mu \overrightarrow{b_2} . . . (2) \]

\[\text{ Here }, \]

\[ \overrightarrow{a_2} = - \hat{i} + 2 \hat{j} + 2 \hat{k} \]

\[ \overrightarrow{b_2} = 5 \hat{i} + \hat{j}  + 0 \hat{k} \]

Now,

\[\overrightarrow{a_2} - \overrightarrow{a_1} = - 2 \hat{i} + 3 \hat{j}  + 2 \hat{k}  \]

\[\text{ and } \overrightarrow{b_1} \times \overrightarrow{b_2} = \begin{vmatrix}\hat{i}  & \hat{j}  & \hat{k}  \\ 2 & 3 & 1 \\ 5 & 1 & 0\end{vmatrix}\]

\[ = - \hat{i}  + 5 \hat{j} - 13 \hat{k}  \]

\[\left( \overrightarrow{a_2} - \overrightarrow{a_1} \right) . \left( \overrightarrow{b_1} \times \overrightarrow{b_2} \right) = \left( - 2 \hat{i} + 3 \hat{j} + 2 \hat{k} \right) . \left( - \hat{i} + 5 \hat{j} - 13 \hat{k} \right)\]

\[ = 2 + 15 - 26\]

\[ = - 9\]

\[\text{ We observe } \]

\[\left( \overrightarrow{a_2} - \overrightarrow{a_1} \right) . \left( \overrightarrow{b_1} \times \overrightarrow{b_2} \right) \neq 0\]

\[\text{ Thus, the given lines do not intersect } .\]

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पाठ 27: Straight Line in Space - Exercise 28.5 [पृष्ठ ३८]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 27 Straight Line in Space
Exercise 28.5 | Q 3.3 | पृष्ठ ३८

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