मराठी

Find the Equation of a Line Perpendicular to the Line √ 3 X − Y + 5 = 0 and at a Distance of 3 Units from the Origin.

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प्रश्न

Find the equation of a line perpendicular to the line \[\sqrt{3}x - y + 5 = 0\] and at a distance of 3 units from the origin.

थोडक्यात उत्तर
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उत्तर

The line perpendicular to \[\sqrt{3}x - y + 5 = 0\] is \[x + \sqrt{3}y + \lambda = 0\]

It is given that the line \[x + \sqrt{3}y + \lambda = 0\] is at a distance of 3 units from the origin.

\[\therefore \left| \frac{\lambda}{\sqrt{1 + 3}} \right| = 3\]

\[ \Rightarrow \lambda = \pm 6\]

Substituting the value of \[\lambda\] we get \[x + \sqrt{3}y \pm 6 = 0\] ,which is  equation of the required line.

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पाठ 23: The straight lines - Exercise 23.12 [पृष्ठ ९३]

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आर.डी. शर्मा Mathematics [English] Class 11
पाठ 23 The straight lines
Exercise 23.12 | Q 23 | पृष्ठ ९३

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