मराठी

Find the Distance Between the Planes 2x - Y + 2z = 5 and 5x - 2.5y + 5z = 20

Advertisements
Advertisements

प्रश्न

Find the distance between the planes 2x - y +  2z = 5 and 5x - 2.5y + 5z = 20

Advertisements

उत्तर १

`2/5 = - 1/(-2.5) = 2/5`

`2/5 = 2/5  = 2/5`

⇒ parallel planes

`5x - 5/2 y + 5z= 20 xx 2/5`

`=> 2x - y + 2z = 8` and `2x - y + 2z = 5`

`=> d = |(8-5)/sqrt(4+1+4)| = 3/sqrt9 = "1 unit"`

shaalaa.com

उत्तर २

Consider the equations of planes, 2x – y + 2z = 5 and 5x – 2.5y + 5z = 20.

Here, we can see the above two planes are parallel planes.

As, 5x – 2.5y + 5z = 20 can also be written as 2x – y + 2z = 8

If the equation of two parallel planes are

ax + by + cz + d1 = 0 and ax + by + cz + d2 = 0

Then, distance between the two parallel planes is given by:

`d = |(d_2 - d_1)/sqrt(a^2 +b^2 +c^2)|`

let us take the two parallel planes be 2– y + 2= 5 and 2x – y + 2z = 8

Therefore the distance is given by:

`d = |(5-8)/(sqrt(2^2 + (-1)^2 +2^2))|`

= `|(-3)/(sqrt(2^2 + (-1)^2) + 2^2)|`

= `|(-3)/sqrt(4+1+4)|`

= `|(-3)/3|`

= 1

Hence the distance between the given two planes is 1 units.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2016-2017 (March) All India Set 1

संबंधित प्रश्‍न

Find the shortest distance between the lines

`bar r = (4 hat i - hat j) + lambda(hat i + 2 hat j - 3 hat k)`

and

`bar r = (hat i - hat j + 2 hat k) + mu(hat i + 4 hat j -5 hat k)`

where λ and μ are parameters

 

Show that the following two lines are coplanar:

`(x−a+d)/(α−δ)= (y−a)/α=(z−a−d)/(α+δ) and (x−b+c)/(β−γ)=(y−b)/β=(z−b−c)/(β+γ)`


Find the shortest distance between the lines: 

`vecr = (hati+2hatj+hatk) + lambda(hati-hatj+hatk)` and `vecr = 2hati - hatj - hatk + mu(2hati + hatj + 2hatk)`


Find the shortest distance between the lines whose vector equations are `vecr = (hati + 2hatj + 3hatk) + lambda(hati - 3hatj + 2hatk)` and `vecr = 4hati + 5hatj + 6hatk + mu(2hati + 3hatj + hatk)`.


Find the shortest distance between lines `vecr = 6hati + 2hatj + 2hatk + lambda(hati - 2hatj + 2hatk)` and `vecr =-4hati - hatk + mu(3hati - 2hatj - 2hatk)`.


Find the shortest distance between the lines `(x+1)/7=(y+1)/(-6)=(z+1)/1 and (x-3)/1=(y-5)/(-2)=(z-7)/1`


Find the shortest distance between the lines `vec r = hat i + 2hat j + 3 hat k +  lambda(2 hat i +  3hatj +  4hatk)` and `vec r =  2hat i +  4 hat j + 5 hat k +  mu (4hat i + 6 hat j +  8 hat k)`


Find the shortest distance between the lines

\[\frac{x - 2}{- 1} = \frac{y - 5}{2} = \frac{z - 0}{3} \text{ and }  \frac{x - 0}{2} = \frac{y + 1}{- 1} = \frac{z - 1}{2} .\]
 

Find the shortest distance between the lines 

\[\frac{x + 1}{7} = \frac{y + 1}{- 6} = \frac{z + 1}{1} \text{ and } \frac{x - 3}{1} = \frac{y - 5}{- 2} = \frac{z - 7}{1} .\]
 

Find the shortest distance between the lines given by `vec"r" = (8 + 3lambdahat"i" - (9 + 16lambda)hat"j" + (10 + 7lambda)hat"k"` and `vec"r" = 15hat"i" + 29hat"j" + 5hat"k" + mu(3hat"i" + 8hat"j" - 5hat"k")`


The fuel cost per hour for running a train is proportional to the square of the speed it generates in km per hour. If the fuel costs ₹ 48 per hour at a speed of 16 km per hour and the fixed charges to run the train amount to ₹ 1200 per hour. Assume the speed of the train as v km/h.

The fuel cost for the train to travel 500 km at the most economical speed is:


The fuel cost per hour for running a train is proportional to the square of the speed it generates in km per hour. If the fuel costs ₹ 48 per hour at a speed of 16 km per hour and the fixed charges to run the train amount to ₹ 1200 per hour. Assume the speed of the train as v km/h.

The total cost of the train to travel 500 km at the most economical speed is:


Distance between the planes :- 

`2x + 3y + 4z = 4` and `4x + 6y + 8z = 12` is


Read the following passage and answer the questions given below.

Two motorcycles A and B are running at the speed more than the allowed speed on the roads represented by the lines `vecr = λ(hati + 2hatj - hatk)` and `vecr = (3hati + 3hatj) + μ(2hati + hatj + hatk)` respectively.

Based on the above information, answer the following questions:

  1. Find the shortest distance between the given lines.
  2. Find the point at which the motorcycles may collide.

Find the shortest distance between the following lines:

`vecr = 3hati + 5hatj + 7hatk + λ(hati - 2hatj + hatk)` and `vecr = (-hati - hatj - hatk) + μ(7hati - 6hatj + hatk)`.


If the shortest distance between the lines `vecr_1 = αhati + 2hatj + 2hatk + λ(hati - 2hatj + 2hatk)`, λ∈R, α > 0 `vecr_2 = - 4hati - hatk + μ(3hati - 2hatj - 2hatk)`, μ∈R is 9, then α is equal to ______.


The largest value of a, for which the perpendicular distance of the plane containing the lines `vec"r" = (hat"i" + hat"j") + λ(hat"i" + "a"hat"j" - hat"k")` and `vec"r" = (hat"i" + hat"j") + μ(-hat"i" + hat"j" - "a"hat"k")` from the point (2, 1, 4) is `sqrt(3)`, is ______.


If the shortest distance between the lines `(x - 1)/2 = (y - 2)/3 = (z - 3)/λ` and `(x - 2)/1 = (y - 4)/4 = (z - 5)/5` is `1/sqrt(3)`, then the sum of all possible values of λ is ______.


The shortest distance between the z-axis and the line x + y + 2z – 3 = 0 = 2x + 3y + 4z – 4, is ______.


Find the distance between the lines:

`vecr = (hati + 2hatj - 4hatk) + λ(2hati + 3hatj + 6hatk)`;

`vecr = (3hati + 3hatj - 5hatk) + μ(4hati + 6hatj + 12hatk)`


An aeroplane is flying along the line `vecr = λ(hati - hatj + hatk)`; where 'λ' is a scalar and another aeroplane is flying along the line `vecr = hati - hatj + μ(-2hatj + hatk)`; where 'μ' is a scalar. At what points on the lines should they reach, so that the distance between them is the shortest? Find the shortest possible distance between them.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×