मराठी

Find d∫2810-xx+10-xdx

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प्रश्न

Find `int_2^8 sqrt(10 - x)/(sqrt(x) + sqrt(10 - x)) "d"x`

बेरीज
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उत्तर

We have I = `int_2^8 sqrt(10 - x)/(sqrt(x) + sqrt(10 - x)) "d"x`  .....(1)

= `int_2^8 sqrt(10 - (10 - x))/(sqrt(10 - x) + sqrt(10 - (10 - x)) "d"x`  .....By (P3)

⇒ I = `int_2^8 sqrt(x)/(sqrt(10 - x) + sqrt(x)) "d"x`  ....(2)

Adding (1) and (2), we get

2I = `int_2^8 1"d"x = 8 - ` = 6

Hence I = 3

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पाठ 7: Integrals - Solved Examples [पृष्ठ १५२]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
पाठ 7 Integrals
Solved Examples | Q 11 | पृष्ठ १५२

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