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प्रश्न
Find `int_0^(pi/4) sqrt(1 + sin 2x) "d"x`
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उत्तर
We have I = `int_0^(pi/4) sqrt(1 + sin 2x) "d"x`
= `int_0^(pi/4) sqrt((sinx + cosx)^2) "d"x`
= `int_0^(pi/4) (sinx + cosx) "d"x`
= `(-cosx + sinx)_0^(pi/4)`
I = 1.
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