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Figure shows (x, t), (y, t ) diagram of a particle moving in 2-dimensions. (a) (b) If the particle has a mass of 500 g, find the force (direction and magnitude) acting on the particle.

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प्रश्न

Figure shows (x, t), (y, t ) diagram of a particle moving in 2-dimensions.


(a)


(b)

If the particle has a mass of 500 g, find the force (direction and magnitude) acting on the particle.

टीपा लिहा
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उत्तर

Clearly, from the diagram (a), the variation can be related as x = t

⇒ `(dx)/(dt)` = 1 m/s

ax = 0

From diagram (b) y = t2

⇒ `(dy)/(dt)` = 2t or ay = `(d^2y)/(dt^2)` = 2 m/s2

Hence, Iy = may = 500 × 10–3 × 2 = 1 N  .....(∵ m = 500 g)

Fx = max = 0

Hence, net force, F = `sqrt(F_x^2 + F_y^2)` = Fy = 1 N  .....(along y-axis)

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पाठ 5: Laws of Motion - Exercises [पृष्ठ ३५]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 11
पाठ 5 Laws of Motion
Exercises | Q 5.32 | पृष्ठ ३५

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