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Evaluate the following : limx→0[ex+e-x-2x⋅tanx] - Mathematics and Statistics

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प्रश्न

Evaluate the following :

`lim_(x -> 0)[("e"^x + "e"^-x - 2)/(x*tanx)]`

बेरीज
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उत्तर

`lim_(x -> 0) ("e"^x + "e"^-x - 2)/(xtanx)`

= `lim_(x -> 0) ("e"^x+1/"e"^x-2)/(xtanx)`

= `lim_(x -> 0) (("e"^x)^2 + 1 - 2("e"^x))/("e"^x*xtanx)`

= `lim_(x -> 0) ("e"^x - 1)^2/("e"^x *xtanx)`

= `lim_(x -> 0) [(("e"^x - 1)^2/x^2)]/[(("e"^x*xtanx)/x^2)]`  ...[∵ x → 0; ∴ x ≠ 0]

= `lim_(x -> 0) (("e"^x - 1)/x)^2/("e"^x*(tanx/x))`

= `(lim_(x -> 0)("e"^x - 1)/x)^2/(lim_(x -> 0)"e"^x*lim_(x -> 0)(tanx/x))`

= `(1)^2/("e"^0*1)`

= 1

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Limits of Exponential and Logarithmic Functions
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Limits - Miscellaneous Exercise 7.2 [पृष्ठ १५९]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
पाठ 7 Limits
Miscellaneous Exercise 7.2 | Q II. (8) | पृष्ठ १५९

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