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प्रश्न
Evaluate the definite integral:
`int_0^(pi/4) tan x dx`
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उत्तर
`int_0^(pi/4) tan x dx`
`= [log sec x]_0^(pi/4)`
`= log sec pi/4 - log sec 0`
`= log sqrt2 - log 1`
`= log sqrt2 = log 2^(1/2)`
`= 1/2 log 2`
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