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प्रश्न
Evaluate the definite integral:
`int_2^3 dx/(x^2 - 1)`
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उत्तर
`int_2^3 dx/ (x^2 - 1)`
`= [1/2 log ((x - 1)/ (x + 1))]_2^3`
`= 1/2 [log ((3-1)/(3 + 1)) - log ((2 - 1)/(2+1))]`
`= 1/2 [log (2/4) - log (1/3)]`
`= 1/2 log ((2/4)/ (1/3))`
`= 1/2 log 3/2`
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