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प्रश्न
Evaluate the definite integral:
`int_0^(pi/4) sin2xdx`
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उत्तर
Let `I = int_0^(pi/4) sin 2x dx`
`= (-1)/2 [cos 2x]_0^(pi/4)`
`= (-1)/2 (cos pi/2 - cos 0)`
`= 1/2`
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