मराठी

Evaluate: Cot 2 41 ° Tan 2 49 ° − 2 Sin 2 75 ° Cos 2 15 °

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प्रश्न

Evaluate: `(cot^2 41°)/(tan^2 49°) - 2 (sin^2 75°)/(cos^2 15°)`

मूल्यांकन
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उत्तर

`(cot^2 41°)/(tan^2 49°) - 2 (sin^2 75°)/(cos^2 15°)`

tan(49°) = cot(41°)

(because 49° + 41° = 90°)

`(cot^2 41°)/(tan^2 49°) = (cot^2 41°)/(cot41°)^2 = 1`

`(sin^2 75°)/(cos^2 15°)`

sin75° = cos15°

`(sin^2 75°)/(cos^2 15°) = (cos15°)^2/(cos15°)^2 = 1`

1 − 2(1) = 1 − 2

= −1

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पाठ 21: Trigonometrical Ratios [Sine, Consine, Tangent of an Angle and their Reciprocals] - EXERCISE 21 (F) [पृष्ठ ३३४]

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सेलिना Concise Mathematics [English] Class 9 ICSE
पाठ 21 Trigonometrical Ratios [Sine, Consine, Tangent of an Angle and their Reciprocals]
EXERCISE 21 (F) | Q 7. (vii) | पृष्ठ ३३४
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