Advertisements
Advertisements
प्रश्न
Evaluate:
`(5sin66^@)/(cos24^@) - (2cot85^@)/(tan5^@)`
Advertisements
उत्तर
`(5sin66^@)/(cos24^@)-(2cot85^@)/(tan5^@)`
= `(5sin(90^@ - 24^@))/(cos24^@) - (2cot(90^@ - 5^@))/(tan5^@)`
= `(5cos24^@)/(cos24^@) - (2tan5^@)/(tan5^@)`
= 5 – 2
= 3
संबंधित प्रश्न
Evaluate `(tan 26^@)/(cot 64^@)`
Show that : sin 42° sec 48° + cos 42° cosec 48° = 2
For triangle ABC, show that : `sin (A + B)/2 = cos C/2`
Find the value of angle A, where 0° ≤ A ≤ 90°.
cos (90° – A) . sec 77° = 1
Evaluate:
`sec26^@ sin64^@ + (cosec33^@)/sec57^@`
If θ is an acute angle such that \[\cos \theta = \frac{3}{5}, \text{ then } \frac{\sin \theta \tan \theta - 1}{2 \tan^2 \theta} =\] \[\cos \theta = \frac{3}{5}, \text{ then } \frac{\sin \theta \tan \theta - 1}{2 \tan^2 \theta} =\]
If tan2 45° − cos2 30° = x sin 45° cos 45°, then x =
If x tan 45° cos 60° = sin 60° cot 60°, then x is equal to
Prove that :
tan5° tan25° tan30° tan65° tan85° = \[\frac{1}{\sqrt{3}}\]
Find the value of the following:
`cot theta/(tan(90^circ - theta)) + (cos(90^circ - theta) tantheta sec(90^circ - theta))/(sin(90^circ - theta)cot(90^circ - theta)"cosec"(90^circ - theta))`
